Answer:
0.246 kg
Explanation:
There is some info missing. I think this is the original question.
<em>A chemist adds 370.0mL of a 2.25 M iron(III) bromide (FeBr₃) solution to a reaction flask. Calculate the mass in kilograms of iron(III) bromide the chemist has added to the flask. Be sure your answer has the correct number of significant digits.</em>
<em />
We have 370.0 mL of 2.25 M iron(III) bromide (FeBr₃) solution. The moles of FeBr₃ are:
0.3700 L × 2.25 mol/L = 0.833 mol
The molar mass of iron(III) bromide is 295.56 g/mol. The mass corresponding to 0.833 moles is:
0.833 mol × 295.56 g/mol = 246 g
1 kilogram is equal to 1000 grams. Then,
246 g × (1 kg/1000 g) = 0.246 kg
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Answer:
According to the law of conservation of mass, the mass of the reacting substances is equal to the mass of the product formed during a reaction.
Explanation:
<h3>
Answer:</h3>
0.643 moles
<h3>
Explanation:</h3>
We are given;
Density of nitrogen gas as 1.20 g/L
Volume nitrogen as 15.0 L
We are required to calculate the number moles of nitrogen gas;
<h3>Step 1: Determine the mass of nitrogen gas</h3>
We know the density is given by dividing mass by volume.
Therefore, to get the mass;
- Mass = Density × volume
- Mass = 1.20 g/L × 15.0 L
= 18 g
<h3>Step 2: Determine the mass of nitrogen gas </h3>
We know that to get the number of moles, we divide mass by molar mass;
That is, moles = Mass ÷ Molar mass
But, molar mass of nitrogen gas is 28 g/mol
Therefore;
Moles of nitrogen gas = 18 g ÷ 28 g/mol
= 0.643 moles
Therefore, the number of moles of nitrogen gas 0.643 moles
1.)1mps
2)no the slope starts to become steady
3.)there is no motion it stops
