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2 years ago

Is it possible to produce a blood type AB from blood type A and B

Chemistry

1 answer:

Masja [62]2 years ago

3 0

Answer:

Yes, it is possible to produce a blood type AB from blood type A and B.

Explanation:

If we were to do a hybrid cross and the mother's blood type was A, then her genotypes would be AA and AO. Additionally, if the father had type B blood, his genotypes would be BB and BO. From this, we can tell that the child's genotypes would have to be A, AB, B, O. Since AB is one of the choices, yes, it is possible to produce a blood type AB from blood type A and B.

The only times where you won't be able to produce a child with type AB is if both of the parents have type B blood and type O blood. Or if one parent has type B blood and the another has type O blood. Or if one parent has type AB and the other one has O blood. Or if both parents have type A blood.

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Problem Page Question It takes to break a carbon-carbon single bond. Calculate the maximum wavelength of light for which a carbo

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This is a incomplete question. The complete question is:

It takes 348 kJ/mol to break a carbon-carbon single bond. Calculate the maximum wavelength of light for which a carbon-carbon single bond could be broken by absorbing a single photon. Round your answer to correct number of significant digits

Answer: 344 nm

Explanation:

$E=\frac{Nhc}{\lambda}$

E= energy = 348kJ= 348000 J (1kJ=1000J)

N = avogadro's number = $6.023\times 10^{23}$

h = Planck's constant = $6.626\times 10^{-34}Js
$

c = speed of light = $3\times 10^8ms^{-1}$

$348000=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}\times 3\times 10^8}{\lambda}$

$\lambda=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}\times 3\times 10^8}{348000}$

$\lambda=3.44\times 10^{-7}m=344nm$ $1nm=10^{-9}m$

Thus the maximum wavelength of light for which a carbon-carbon single bond could be broken by absorbing a single photon is 344 nm

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