Solid state of matter
- the atoms are tightly packed in orderly form, they slightly vibrate but are stuck in a fixed position. Solids cannot be compressed and they maintain their shape
Atomic number of an element is the number of protons present in that element. It is unique for each element. The atomic number of carbon is 6.
.. What is the sum of 6.078g and 0.3329g? What is the .... type on a calculator<span> 100.80 divided by 28 which equals 3.6.</span>
Answer:At higher elevations, there are fewer air molecules above a given surface than a similar surface at lower levels. ... Since more than half of the atmosphere's molecules are located below an altitude of 5.5 km, atmospheric pressure decreases roughly 50% (to around 500 mb) within the lowest 5.5 km.
Explanation:brainliest plz
Solution :
When non volatile solute is added to solvent, vapor pressure gets lowered.
Relative lowering in vapor pressure is given :
=
of solute
![$\frac{P^0-P}{P^0}=x_B$](https://tex.z-dn.net/?f=%24%5Cfrac%7BP%5E0-P%7D%7BP%5E0%7D%3Dx_B%24)
= vapor pressure of pure solvent
P = vapor pressure of solution
= mole fraction of solute
![$x_B=\frac{n_B}{n_A+n_B}$](https://tex.z-dn.net/?f=%24x_B%3D%5Cfrac%7Bn_B%7D%7Bn_A%2Bn_B%7D%24)
= ![$\text{number of moles of solute}$](https://tex.z-dn.net/?f=%24%5Ctext%7Bnumber%20of%20moles%20of%20solute%7D%24)
= ![$\text{number of moles of solvent}$](https://tex.z-dn.net/?f=%24%5Ctext%7Bnumber%20of%20moles%20of%20solvent%7D%24)
Number of moles ![$=\frac{\text{weight}}{\text{molecular weight}}$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B%5Ctext%7Bweight%7D%7D%7B%5Ctext%7Bmolecular%20weight%7D%7D%24)
![$\frac{P^0-P}{P^0}=\frac{w_B/M_B}{w_A/M_A+w_B/M_B}$](https://tex.z-dn.net/?f=%24%5Cfrac%7BP%5E0-P%7D%7BP%5E0%7D%3D%5Cfrac%7Bw_B%2FM_B%7D%7Bw_A%2FM_A%2Bw_B%2FM_B%7D%24)
![$\approx \frac{w_B/M_B}{w_A/M_A}$](https://tex.z-dn.net/?f=%24%5Capprox%20%5Cfrac%7Bw_B%2FM_B%7D%7Bw_A%2FM_A%7D%24)
1. For 10 g of ![$CH_3COOK$](https://tex.z-dn.net/?f=%24CH_3COOK%24)
![$CH_3COOK \rightarrow CH_3COO^- + K^+$](https://tex.z-dn.net/?f=%24CH_3COOK%20%5Crightarrow%20CH_3COO%5E-%20%2B%20K%5E%2B%24)
Ions = 2
It will affect colligative property.
![$\frac{P^0-P}{P^0} = \frac{i \times 10/98}{w_A/M_A}$](https://tex.z-dn.net/?f=%24%5Cfrac%7BP%5E0-P%7D%7BP%5E0%7D%20%3D%20%5Cfrac%7Bi%20%5Ctimes%2010%2F98%7D%7Bw_A%2FM_A%7D%24)
Relative lowering in vapor pressure will be :
![$=\frac{2 \times 10/98}{w_A/M_A}$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B2%20%5Ctimes%2010%2F98%7D%7Bw_A%2FM_A%7D%24)
![$=\frac{0.20}{w_A/M_A}$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B0.20%7D%7Bw_A%2FM_A%7D%24)
2. For 20 g sucrose
Sucrose is non electrolyte, i = 1
![$\frac{P^0-P}{P^0} = \frac{ 20/342}{w_A/M_A}$](https://tex.z-dn.net/?f=%24%5Cfrac%7BP%5E0-P%7D%7BP%5E0%7D%20%3D%20%5Cfrac%7B%2020%2F342%7D%7Bw_A%2FM_A%7D%24)
![$=\frac{0.050}{w_A/M_A}$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B0.050%7D%7Bw_A%2FM_A%7D%24)
3. For 20 g of glucose.
Glucose is a non electrolyte, i = 1
![$\frac{P^0-P}{P^0} = \frac{20/180}{w_A/M_A}$](https://tex.z-dn.net/?f=%24%5Cfrac%7BP%5E0-P%7D%7BP%5E0%7D%20%3D%20%5Cfrac%7B20%2F180%7D%7Bw_A%2FM_A%7D%24)
![$=\frac{0.11}{w_A/M_A}$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B0.11%7D%7Bw_A%2FM_A%7D%24)
is same in all three solutions.
Hence, lowering in vapor pressure is maximum in
and minimum is Sucrose.
Vapor pressure from lowest to highest.
10 g of
< 20 g of glucose < 20 g of sucrose