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bekas [8.4K]
3 years ago
7

Enter your answer in the provided box. On a certain winter day in Utah, the average atmospheric pressure is 718 torr. What is th

e molar density (in mol/L) of the air if the temperature is −29°C?
Chemistry
1 answer:
AnnZ [28]3 years ago
7 0

Answer:

The correct answer is 0.047 mol/L

Explanation:

The atmospheric air is a mixture of gases. We can assume an ideal behavior of the gas and use the ideal gas equation:

PV= nRT

where P is the pressure, V is the volume, n is the number of moles, R is a constant (0.082 L.atm/K.mol) and T is the temperature in K.

We have to first convert the pressure from Torr to atm:

760 Torr= 1 atm

⇒ 718 Torr x 1 atm/760 Torr = 0.945 atm

Then, we convert the temperature from ºC to K:

0ºC = 273 K

⇒ -29ºC+273= 244 K

Finally, we introduce the data in the equation and calculate de densitiy, which is the moles per liters of gas (n/V):

PV = nRT

n/V= P/RT

n/V = (0.945 atm)/(0.082 L.atm/K.mol x 244 K) = 0.047 mol/L

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Answer:

Determine the mass of substance and it's molar mass. Divide the given mass by it's molar mass to get moles and multiply time

6.002*1023 molecules 1mole

5 0
2 years ago
A 400 mL sample of hydrogen gas is collected over water at 20°C and 760 torr the vapor pressure of water at 20°C is 17.5 torr. w
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Answer:

V2 = 17371.43ml

Explanation:

We use Boyles laws

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4 0
3 years ago
O, li, c which electrons experience the greatest effective nuclear charge? express your answer as a chemical formula.
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3 years ago
A 2.36-gram sample of NaHCO3 was completely decomposed in an experiment.
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Answer:

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b) The gram-formula mass of sodium bicarbonate is 84.006 g/mol, meaning that 2.36/84.006 = 0.028 moles were consumed. Thus, this means that in theory, 0.014 moles of carbonic acid should have been produced, which would have a mass of (0.014)(62.024)=0.868 grams. Thus, the percentage yield is (0.79)/(0.868) * 100 = 91%

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