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MrRa [10]
3 years ago
8

When Victoria goes bowling, her scores are normally distributed with a mean of 130

Mathematics
1 answer:
Artemon [7]3 years ago
5 0

Answer:

0.2377 or about a 23.77% chance

Step-by-step explanation:

P(123<X<130) = normalcdf(123,130,130,11) = 0.2377303466 ≈ 0.2377

Therefore, the probability that the next game Victoria bowls, her score will be  between 123 and 130 is 0.2377 or about a 23.77% chance

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