The height of ABC = 2 units.
The height of A'B'C' = 6 units.
Dilation = 6/2 = 3
I belive this is the answer
x³ = 27/125; and
x = 3/5.
explanation:
Reducing the voltage 3 times would result in multiplying the unknown voltage, x, by itself 3 times; this gives us
x³.
The current voltage is 27/125; this gives us the equation
x³ = 27/125.
To solve this, take the cubed root of both sides:
∛(x³) = ∛(27/125)
x = (∛27)/(∛125)
x = (∛(3*3*3))/(∛(5*5*5))
x = 3/5
Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :
B )
Acceleration a is given by :
Hence , this is the required solution .
The length is 24 and the width is 6.
I did a little guess and check here, as when I algebraically solved it, the answers did not make sense. However, the length (24) is 4 times the width (6), and 24 times 6 is 144, so it works!
I hope this helps.
Answer:
A. ⅕
Step-by-step explanation:
÷ 2 = 
÷ 2/5 = 
÷ 2/25 = 
Therefore, the multiplicative rate of change of the function would be ⅕
