2(|x−3|)−4≥10
Step 1: Add 4 to both sides.<span><span><span><span>2<span>(<span>|<span>x−3</span>|</span>)</span></span>−4</span>+4</span>≥<span>10+4</span></span><span><span>2<span>(<span>|<span>x−3</span>|</span>)</span></span>≥14</span>Step 2: Divide both sides by 2.<span><span><span>2<span>(<span>|<span>x−3</span>|</span>)</span></span>2</span>≥<span>142</span></span><span><span>|<span>x−3</span>|</span>≥7</span>Step 3: Solve Absolute Value.<span><span>|<span>x−3</span>|</span>≥7</span>We know either<span><span>x−3</span>≥7</span>or<span><span>x−3</span>≤<span>−7</span></span><span><span>x−3</span>≥7</span>(Possibility 1)<span><span><span>x−3</span>+3</span>≥<span>7+3</span></span>(Add 3 to both sides)<span>x≥10</span><span><span>x−3</span>≤<span>−7</span></span>(Possibility 2)<span><span><span>x−3</span>+3</span>≤<span><span>−7</span>+3</span></span>(Add 3 to both sides)<span>x≤<span>−<span>4
the answer is
</span></span></span><span>x≥<span><span>10<span>or </span></span>x</span></span>≤−4
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The answer is <span>C. 546.
If a population decreases by 11%, that means that 89% (100% - 11% = 89%) of cheetahs remains each number. 89% can be expressed as 0.89, so to calculate the change of the population, we must each year multiply the number of cheetahs by 0.89.
After 1 year: 1750 * 0.89 </span>≈<span> 1558
</span>After 2 years: 1558 * 0.89 ≈<span> 1387
</span>After 3 years: 1387 * 0.89 ≈<span> 1234
</span>After 4 years: 1234 * 0.89 ≈<span> 1098
</span>After 5 years: 1098 * 0.89 ≈<span> 977
</span>After 6 years: 977 * 0.89 ≈<span> 870
</span>After 7 years: 870 * 0.89 ≈ 774
After 8 years: 774 * 0.89 ≈<span> 689
</span>After 9 years: 689 * 0.89 ≈<span> 613
</span>After 10 years: 613 * 0.89 ≈<span> 546</span>
