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zmey [24]
3 years ago
12

Thomas bought a bag of jelly beans that contained 10 red jelly beans, 15 blue jelly beans, and 12 green jelly beans. What is the

probability of Thomas reaching into the bag and pulling out a blue or green jelly bean and then reaching in again and pulling out a red jelly bean? Assume that the first jelly bean is not replaced.
A. 1/100
B. 3
C. 5/74
D. 0
Mathematics
1 answer:
Hitman42 [59]3 years ago
7 0
There are 37 jelly beans so p for the first one is 27/37. That leaves 36 in the bag. So p for the second jelly bean is 10/36=5/18.
The combine probability is 27/37×5/18=3/37×5/2=15/74.
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Answer:

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Step-by-step explanation:

We can start by changing this number to a fraction.

\frac{9}{100}

We know that 100 is a whole percentage

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What is Lim x → ∞ cos (x) ?
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non existent

Step-by-step explanation:

Hello, please consider the following.

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3 years ago
Evaluate f (x) = 3 (2)x for x=-1
kap26 [50]

The value of the function at x = -1 is 5

<h3>What is  function?</h3>

Function can be defined as an expression, rule, or law that defines a relationship between one variable known as the independent variable and another called the dependent variable.

From the information given, we have that;

f (x) = 3 (2)x  with  x=-1

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8 0
2 years ago
Please help
Liono4ka [1.6K]

Answer:

P(red) = .3

P(yellow) = .3

75 cubes in the box

Step-by-step explanation:

The probability has to add to 1

Since the number of red cubes equals the number of yellow cubes the probability has to be the same

.4 + x+x = 1

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2x = 1-.4

2x = .6

Divide by 2

x = .6/2

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P(red) = .3

P(yellow) = .3

We know that

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7 0
3 years ago
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