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zmey [24]
3 years ago
12

Thomas bought a bag of jelly beans that contained 10 red jelly beans, 15 blue jelly beans, and 12 green jelly beans. What is the

probability of Thomas reaching into the bag and pulling out a blue or green jelly bean and then reaching in again and pulling out a red jelly bean? Assume that the first jelly bean is not replaced.
A. 1/100
B. 3
C. 5/74
D. 0
Mathematics
1 answer:
Hitman42 [59]3 years ago
7 0
There are 37 jelly beans so p for the first one is 27/37. That leaves 36 in the bag. So p for the second jelly bean is 10/36=5/18.
The combine probability is 27/37×5/18=3/37×5/2=15/74.
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3 0
2 years ago
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Hope it helps :)

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Students collected 150 cans for a food drive. there were 23 cans of corn, 48 cans of beans, and 12 cans of tomato sauce. if a st
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Hello!

\bf Answer:

The probability that the can will be either tomato sauce or beans is \bf \frac{2}{5}.

___________________________________________________

\bf Explanation:

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2 years ago
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3 years ago
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ANSWER: y = \frac{3-5x}{-2}

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