3 years ago

1. Find the exact value of sin and cos of 195 degrees.

Mathematics

1 answer:

KengaRu [80]3 years ago

5 0

Answer:

Sin195* = - $\frac{\sqrt{6}-\sqrt{2} }{4 }$

Cos195* = - $\frac{\sqrt{6} +\sqrt{2} }{4}$

Step-by-step explanation:

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Sophie [7]

The idea is to use the tangent line to $f(x)=\sqrt x$ at $x=25$ in order to approximate $f(25.3)=\sqrt{25.3}$ .

We have

$f(x)=\sqrt x\implies f(25)=\sqrt{25}=5$

$f'(x)=\dfrac1{2\sqrt x}\implies f'(25)=\dfrac1{10}$

so the linear approximation to $f(x)$ is

$L(x)=f(5)+f'(5)(x-5)=5+\dfrac{x-5}{10}=\dfrac x{10}+\dfrac92$

Hence $m=\frac1{10}$ and $b=\frac92$ .

Then

$f(25.3)\approx L(25.3)=\dfrac{25.3}{10}+\dfrac92=\boxed{7.03}$

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photoshop1234 [79]

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Explanation:

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2 years ago

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Paul [167]

Answer:

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Step-by-step explanation:

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