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disa [49]
3 years ago
10

What is the quotient of 5,256 ÷ 52?

Mathematics
1 answer:
denis23 [38]3 years ago
3 0

Answer:

5,256 - 4 = 5,252 = 52 x 101 or 101.0769230769231

Step-by-step explanation:

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-2,-4,-14,-16 and -37 greastest from least​
Keith_Richards [23]
-37,-16,-14,-4,-2 is the answer
3 0
3 years ago
If the surface area of the box in the diagram is 204.25 square feet, what is the value of ‘x’?
Alexandra [31]

Note: Consider x be the breadth of the box.

Given:

The surface area of the box is 204.25 square feet.

Length of the box = 10 ft

Breadth of the box = x ft

Height of the box = 6.5 ft

To find:

The value of x.

Solution:

The surface area of a cuboid is:

SA=2(lb+bh+hl)

Where, l is length, b is breadth and h is height of the cuboid.

Putting SA=204.25,  l=10,\ b=x,\ h=6.5 in the above formula, we get

204.25=2(10\times x+x\times 6.5+6.5\times 10)

204.25=2(10x+6.5x+65)

204.25=2(16.5x+65)

Using distributive property, we get

204.25=2(16.5x)+2(65)

204.25=33x+130

204.25-130=33x

74.25=33x

Divide both sides by 33.

\dfrac{74.25}{33}=x

2.25=x

Therefore, the correct option is B.

7 0
3 years ago
Anyone help me please?
solmaris [256]
For the first one false false and the second on is true true
4 0
2 years ago
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4> Solve by using Laplace transform: y'+5y'+4y=0; y(0)=3 y'(o)=o
harina [27]

Answer:

y=3e^{-4t}

Step-by-step explanation:

y''+5y'+4y=0

Applying the Laplace transform:

\mathcal{L}[y'']+5\mathcal{L}[y']+4\mathcal{L}[y']=0

With the formulas:

\mathcal{L}[y'']=s^2\mathcal{L}[y]-y(0)s-y'(0)

\mathcal{L}[y']=s\mathcal{L}[y]-y(0)

\mathcal{L}[x]=L

s^2L-3s+5sL-3+4L=0

Solving for L

L(s^2+5s+4)=3s+3

L=\frac{3s+3}{s^2+5s+4}

L=\frac{3(s+1)}{(s+1)(s+4)}

L=\frac3{s+4}

Apply the inverse Laplace transform with this formula:

\mathcal{L}^{-1}[\frac1{s-a}]=e^{at}

y=3\mathcal{L}^{-1}[\frac1{s+4}]=3e^{-4t}

7 0
3 years ago
P pennies added to 22 pennies
taurus [48]
23 Pennie’s is the answer I believe
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