Question

Gressel the Goblin is making an inventory of Darklord Ganondorf’s treasure horde following a raid by some violent fellow named link. The horde now contains only 2150 gems (as in $). Gressel notices that there were twice as many green-gems (worth 1) as blue-gems (worth 5) and 13 fewer blue gems than red-gems (worth 20). How many red, blue and green gems are there remaining in the horde?
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Answer 1

Explanation:

Let  the   number of blue  gems  =  B

Let  the number of   green gems  = 2B

Let  the  number of red  gems = B + 13

 

So

 

5B  + 1*2B  + 20 ( B + 13)  =  2150   simplify

 

27B + 260 =  2150

 

27B  = 2150 - 260

 

27B  = 1890

 

B =  1890 / 27  =  70   blue gems

 

2*70  =  140  green gems

 

70 + 13  =  83  red gems

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Answer 2

➥ Let the number of blue gems be x, green gems be 2x and red gems be x + 13.

According to question,

5x + 1 × 2x + 20(x + 13) = 2150

On solving equation, we get

27x + 260 = 2150

27x = 2150 - 260

27x = 1890

x = 1890/27 = 70 blue gems.

2 × 70 = 140 green gems.

70 + 13 = 83 red gems.

Hence, We have 70 blue gems, 140 green gems and 83 red gems.