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d1i1m1o1n [39]
2 years ago
11

This cube's sides each measure 8 cm. Find the length of the diagonal of the cube.

Mathematics
1 answer:
topjm [15]2 years ago
6 0

Answer:

13.856406460551 m

Step-by-step explanation:

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If h(-8), find 1/3*h(x) = x^2-5x+7
Lynna [10]

The value is 333

<h3>How to determine the function</h3>

From the information given, we have:

  • x = - 8
  • 1/3*h(x) = x^2-5x+7

Now, let's substitute the value of 'x' in the function:

1/3*h(x) = x^2-5x+7

1/ 3 × h(-8) = ( - 8)² - 5 ( -8) + 7

Make 'h ( -8)' the subject of formula

h ( -8) = \frac{( -8)^2 - 5(-8) + 7}{1/ 3}

h ( -8) = \frac{64 + 40+ 7 }{1/ 3}

Take the sum of the numerator

h ( -8) = \frac{111}{1/3}

Take the inverse of the denominator and multiply

h ( -8) = 111 × 3/ 1

h ( -8) = 333

We can see that through the substitute of the value of x as - 8, we get 333

Thus, the value is 333

Learn more about algebraic expressions here:

brainly.com/question/723406

#SPJ1

7 0
1 year ago
How many elements does A contains if it has 64 subsets​
Amanda [17]
<h3>Answer:  6</h3>

===========================================================

Explanation:

Rule: If a set has n elements in it, then it will have 2^n subsets.

For example, there are n = 3 elements in the set {a,b,c}. This means there are 2^n = 2^3 = 8 subsets. The eight subsets are listed below.

  1. {a,b,c} .... any set is a subset of itself
  2. {a,b}
  3. {a,c}
  4. {b,c}
  5. {a}
  6. {b}
  7. {c}
  8. { } ..... the empty set

Subsets 2 through 4 are subsets with exactly 2 elements.  Subsets 5 through 7 are singletons (aka sets with 1 element). The last subset is the empty set which is a subset of any set. You could use the special symbol \varnothing to indicate the empty set.

For more information, check out concepts relating to the power set.

-------------------

The problem is asking what value of n will make 2^n = 64 true.

You could guess-and-check your way to see that 2^n = 64 has the solution n = 6.

Another approach is to follow these steps.

2^n = 64\\\\2^n = 2^6\\\\n = 6

Which is fairly trivial.

Or you can use logarithms to solve for the exponent.

2^n = 64\\\\\text{Log}\left(2^n\right)=\text{Log}\left(64\right)\\\\n*\text{Log}\left(2\right)=\text{Log}\left(64\right)\\\\n=\frac{\text{Log}\left(64\right)}{\text{Log}\left(2\right)}\\\\n\approx\frac{1.80617997398389} {0.30102999566399} \ \text{ ... using base 10 logs}\\\\n\approx5.99999999999983\\\\

Due to rounding error, we don't land exactly on 6 even though we should.

5 0
2 years ago
Will mark brainliest! 10 points!
Sonbull [250]

im not t he best at math but i think its a base on the question

3 0
3 years ago
$9.40 per hour times 22 hours round to the nearest cent
REY [17]

Answer:

The answer is 206.8. But you want me to round to the nearest cent so the real answer is $207.00

Step-by-step explanation:

4 0
3 years ago
If an unfair coin comes up heads​ 60% of the time and tails​ 40% of the​ time, what is the expectation if heads is valued at 1 a
monitta
I would think the value would be .2 cause if you had 100 tosses you would expect 60 value for heads and -40 value for tails. giving you 20/100
5 0
3 years ago
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