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7nadin3 [17]
3 years ago
6

Help!!!!!!!!!!!!!!!! Answer the red question!!!!!!!!

Physics
2 answers:
aliya0001 [1]3 years ago
8 0
Animals will then have to adapt to their new environment. they might have to change their diet and get new homes.
labwork [276]3 years ago
5 0
Animals will then have to adapt to their new environment. Animals will then have to move to their new environment. Animals <span>will then have to change there diet to their new environment. </span>
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Why is the cycle of cellular respiration and photosynthesis important to life for plants
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The cycle of cellular respiration and photosynthesis are important for the life of plants because cellular respiration uses one of the products of photosynthesis (oxygen), and uses it as one of the reactants along with glucose to produce carbon dioxide. These two cycles help maintain a balance for our atmosphere, even though pollution and other factors have disrupted this balance. Hope this helps! :)
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3 years ago
Where do we use friction in day to day life​
laila [671]

Answer:

walking in ground

while playing carrom

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The position of a 55 g oscillating mass is given by x(t)=(2.0cm)cos(10t), where t is in seconds. determine the velocity at t=0.4
NNADVOKAT [17]
The position of the mass is given by (in cm):
x(t)=2 \cos (10 t)
The velocity is the derivative of the position:
v(t) =  \frac{dx(t)}{dt} =-10\cdot 2 \sin (10t)=-20 \sin (10t)
Substituting t=0.40 s, we can find the velocity at this time:
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5 0
3 years ago
Read 2 more answers
The moon continues to orbit Earth in an example of the law of conservation of
marusya05 [52]
A gravity and or D angular momentum

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3 years ago
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A projectile is launched from ground level with an initial speed of 53.7 m/s. Find the launch angle (the angle the initial veloc
Simora [160]

Answer:\theta =75.52^{\circ}

Explanation:

Given

initial speed of Launch(u)=53.7 m/s

Range of Projectile =Maximum height of Projectile

Range is given by R=\frac{u^2\sin 2\theta }{g}

Maximum height is given by H_{max}=\frac{u^2\sin ^2\theta }{2g}

R=H_{max}

\frac{u^2\sin 2\theta }{g}=\frac{u^2\sin ^2\theta }{2g}

\frac{u^2\sin 2\theta }{g}-\frac{u^2\sin ^2\theta }{2g}=0

\frac{u^2\sin \theta }{g}\cdot \left [ 2\cos \theta -\frac{1}{2}\right ]=0

as u cannot be zero therefore

2\cos \theta -\frac{1}{2}=0

\cos \theta =\frac{1}{4}

\theta =75.52^{\circ}

6 0
3 years ago
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