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7nadin3 [17]
3 years ago
6

Help!!!!!!!!!!!!!!!! Answer the red question!!!!!!!!

Physics
2 answers:
aliya0001 [1]3 years ago
8 0
Animals will then have to adapt to their new environment. they might have to change their diet and get new homes.
labwork [276]3 years ago
5 0
Animals will then have to adapt to their new environment. Animals will then have to move to their new environment. Animals <span>will then have to change there diet to their new environment. </span>
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As an object moves along the x axis, many measurements are made of its position, enough to generate a smooth, accurate graph of
Bas_tet [7]
The best and most correct answers among the choices provided by your question are he second and third choices. 
<span>The velocity at any instant the average velocity during some time interval cannot be obtained from the graph alone.</span>


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
6 0
3 years ago
Read 2 more answers
A cyclotron with a magnetic field of 0.47 t is designed to accelerate protons in a circle with a radius 0.68 m. What is the angu
Ghella [55]

The angular frequency of the cyclotron is 0.07 x 10^{8}Hz.

<h3>What is angular frequency?</h3>
  • Angular frequency, abbreviated "ω" is a scalar measure of rotation rate in physics.
  • It describes the rate of change of the argument of the sine function, the rate of change of the phase of a sinusoidal waveform, or the angular displacement per unit of time.
<h3>What is cyclotron?</h3>

The cyclotron device is made to accelerate charge particles to extremely high speeds by applying crossed electric and magnetic fields.

<h3>Calculation of angular frequency:</h3>

Given,

B = 0.47 T

r = 0.68

mass of proton = 1.6x10^{-27}

q = 1.6 x 10^{-19}

so, the frequency is:

f = qB/2\pim

f = 1.6 x 10^{-19} x 0.47/2x3.14x1.6x10^{-27}

f = 0.07 x 10^{8}

Hence, the angular frequency of the cyclotron is  0.07 x 10^{8}Hz.

Learn more about angular frequency here:

brainly.com/question/14244057

#SPJ4

7 0
1 year ago
which of these changes does a submarine encounter as it returns from the bottom of the ocean to the surface of the ocean
fiasKO [112]

a.the amount of sunlight increases.

Explanation:

As a submarine rises to the surface, the change it encounters that is true from the given options is that the amount of sunlight increases.

The bottom of the ocean is dark and receives little to no sunlight due to the scattering of the rays by ocean water.

  • As the submarine rises, the volume of water column on it decreases and the pressure on it decreases too.
  • Also, the temperature rises steadily to the surface.

learn more:

Heat and temperature brainly.com/question/914750

#learnwithBrainly

7 0
3 years ago
Precautions to be taken for the displacement method
finlep [7]

Volume by Displacement. The displacement method (submersion, or dunking method) can be used to accurately measure the volume of the human body and other oddly shaped objects by measuring the volume of fluid displaced when the object is submerged.

The following precautions should be taken very observantly:-

The line of sight must be perpendicular to measuring scale to avoid parallax error. Formation of bubbles inside the cylinder should be completely avoided. Any bubbles within leads to wrong measurements.

8 0
3 years ago
Holly puts a box into the trunk of her car. Later, she drives around an unbanked curve that has a radius of 48 m. The speed of t
LiRa [457]

Answer:

The minimum coefficient of friction is 0.544

Solution:

As per the question:

Radius of the curve, R = 48 m

Speed of the car, v = 16 m/s

To calculate the minimum coefficient of static friction:

The centrifugal force on the box is in the outward direction and is given by:

F_{c} = \frac{mv^{2}}{R}  

f_{s} = \mu_{s}mg

where

\mu_{s} = coefficient of static friction

The net force on the box is zero, since, the box is stationary and is given by:

F_{net} = f_{s} - F_{c}  

0 = f_{s} - F_{c}  

\mu_{s}mg = \frac{mv^{2}}{R}  

\mu_{s} = \frac{v^{2}}{gR}  

\mu_{s} = \frac{16^{2}}{9.8\times 48} = 0.544  

3 0
3 years ago
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