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Kisachek [45]
3 years ago
12

Aaliyah invested $550 in an account paying interest rate of 4% compounded constantly assuming no deposits or withdrawals are mad

e how much money to the nearest cent would be in the account after 20 years I NEED THE ANSWER ASAP PLEASE!!!!!
Mathematics
1 answer:
devlian [24]3 years ago
6 0

Answer:

1224.05

Step-by-step explanation:

formula:

PV(e^(it))

550*e^(.04*20)=1224.0475 which rounds to 1224.05

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Which expression is equivalent to -2(1 - 4n)?
padilas [110]

Answer:

-2+8n

Step-by-step explanation:

we can distribute the -2 inside the parentheses to find an equivalent expression.

-2(1-4n)

(-2)(1)+(-2)(-4n)

-2+8n

there's your answer!

7 0
3 years ago
NEED HELP QUICK!!!!! Eight pounds of cashew nuts cost $32. What is the cost of 1 pound of cashew nuts? A.$2 B.$3 C.$4 D.$8
GenaCL600 [577]
The first step here would be to write out an equation.

$32 ÷ 8 = ?

The reason we are doing thirty-two divided by eight is because this equation will give us the cost of one pound of Cashew Nuts.

Now we solve the equation.

$32 ÷ 8 = 4

So, this means our answer is, The <span>cost of 1 pound of Cashew Nuts is only $4.</span>
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3 years ago
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A random sample of a specific brand of snack bar is tested for calorie count, with the following results: Assume the population
LenKa [72]

Answer:

The 95% confidence interval for the population mean (calorie count of the snacks bars) is (130.32, 161.68).

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>"A random sample of a specific brand of snack bar is tested for calorie count, with the following results: </em><em>149, 145,140,160,149,153,131,134,153</em><em>. Assume the population standard deviation is </em><em>σ=24</em><em> and that the population is approximately normal. Construct a 95% confidence interval for the calorie count of the snack bars."</em>

We start by calculating the mean of the sample:

M=\dfrac{1}{9}\sum_{i=1}^{9}(149+145+140+160+149+153+131+134+153)\\\\\\ M=\dfrac{1314}{9}=146

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is know and is σ=24.

The sample mean is M=146.

The sample size is N=9.

As σ is known, the standard error of the mean (σM) is calculated as: \sigma_M=\dfrac{\sigma}{\sqrt{N}}=\dfrac{24}{\sqrt{9}}=\dfrac{24}{3}=8

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 8=15.68

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 146-15.68=130.32\\\\UL=M+t \cdot s_M = 146+15.68=161.68

The 95% confidence interval for the population mean is (130.32, 161.68).

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