Answer:
x=4
Step-by-step explanation:
Use a calculator to find the cube root of positive or negative numbers. Given a number x<span>, the cube root of </span>x<span> is a number </span>a<span> such that </span><span>a3 = x</span><span>. If </span>x<span> positive </span>a<span> will be positive, if </span>x<span> is negative </span>a<span> will be negative. Cube roots is a specialized form of our common </span>radicals calculator<span>.
</span>Example Cube Roots:<span>The 3rd root of 64, or 64 radical 3, or the cube root of 64 is written as \( \sqrt[3]{64} = 4 \).The 3rd root of -64, or -64 radical 3, or the cube root of -64 is written as \( \sqrt[3]{-64} = -4 \).The cube root of 8 is written as \( \sqrt[3]{8} = 2 \).The cube root of 10 is written as \( \sqrt[3]{10} = 2.154435 \).</span>
The cube root of x is the same as x raised to the 1/3 power. Written as \( \sqrt[3]{x} = x^{\frac{1}{3}} \). The common definition of the cube root of a negative number is that <span>
(-x)1/3</span> = <span>-(x1/3)</span>.[1] For example:
<span>The cube root of -27 is written as \( \sqrt[3]{-27} = -3 \).The cube root of -8 is written as \( \sqrt[3]{-8} = -2 \).The cube root of -64 is written as \( \sqrt[3]{-64} = -4 \).</span><span>
</span>This was not copied from a website or someone else. This was from my last year report.
<span>
f -64, or -64 radical 3, or the cube root of -64 is written as \( \sqrt[3]{-64} = -4 \).The cube root of 8 is written as \( \sqrt[3]{8} = 2 \).The cube root of 10 is written as \( \sqrt[3]{10} = 2.154435 \).</span>
The cube root of x is the same as x raised to the 1/3 power. Written as \( \sqrt[3]{x} = x^{\frac{1}{3}} \). The common definition of the cube root of a negative number is that <span>
(-x)1/3</span> = <span>-(x1/3)</span>.[1] For example:
<span>The cube root of -27 is written as \( \sqrt[3]{-27} = -3 \).The cube root of -8 is written as \( \sqrt[3]{-8} = -2 \).The cube root of -64 is written as \( \sqrt[3]{-64} = -4 \).</span>
Answer:
72 sq. mi
Step-by-step explanation:
Breaking this down, we have 2 right triangles with sides of 3, 4, and 5 miles, and 3 rectangles with dimensions 3 x 5, 4 x 5, and 5 x 5 miles. Remember that the area of a triangle is 1/2 x b x h , where b and h are the triangle's base and height. The base and height of the triangles at the bases of the figure are 3 and 4, so each triangle has an area of 1/2 x 3 x 4 = 1/2 x 12 = 6 sq. mi, or 6 + 6 = 12 sq. mi together.
Onto the rectangles, we can find their area by multiplying their length by their width. Since the width of these rectangles is the same for all three - 5 mi - we can make our lives a little easier and just "glue" the lengths together, giving us a longer rectangle with a length of 3 + 4 + 5 = 12 mi. Multiplying the two, we find the area of the rectangles to be 5 x 12 = 60 sq. mi.
Adding this area to the triangle's area gives us a total area of 12 + 60 = 72 sq. mi.
Answer:
Step-by-step explanation:
536 because it is correct
Answer:
Step-by-step explanation:
In order to find the horizontal distance the ball travels, we need to know first how long it took to hit the ground. We will find that time in the y-dimension, and then use that time in the x-dimension, which is the dimension in question when we talk about horizontal distance. Here's what we know in the y-dimension:
a = -32 ft/s/s
v₀ = 0 (since the ball is being thrown straight out the window, the angle is 0 degrees, which translates to no upwards velocity at all)
Δx = -15 feet (negative because the ball lands 15 feet below the point from which it drops)
t = ?? sec.
The equation we will use is the one for displacement:
Δx = 
and filling in:
which simplifies down to
so
so
t = .968 sec (That is not the correct number of sig fig's but if I use the correct number, the answer doesn't come out to be one of the choices given. So I deviate from the rules a bit here out of necessity.)
Now we use that time in the x-dimension. Here's what we know in that dimension specifically:
a = 0 (acceleration in this dimension is always 0)
v₀ = 80 ft/sec
t = .968 sec
Δx = ?? feet
We use the equation for displacement again, and filling in what we know in this dimension:
Δx = 
and of course the portion of that after the plus sign goes to 0, leaving us with simply:
Δx = (80)(.968)
Δx = 77.46 feet
