A right-angled triangle has one side of length 1.5 cm. Its hypotenuse is 6 cm. How long is its other side?

Scorpion4ik [409]

First you need to find the common denominator. Think of a number that both 2 and 5 can go in to evenly. 10 is the best number, so, make both denominators 10. What you do to the bottom, you must do to the top.
Now your equation is 5/10-2/10
Your answer is 3/10

3 0

3 years ago

URGENT PLEASE I AM TIMED URGENT SOLVE THE PROBLEM AND PLEASE, PLEASE EXPLAIN HOW YOU GOT YOUR ANSWER, GIVE DETAIL'S I WILL MARK

Neko [114]

I'm pretty sure you just multiply the 1 1/4 by 3 because if 1 1/4 makes 10 muffins you need to make 3 more dozens so 1 1/4 times 3 equals 3.75

3 0

2 years ago

Boxes of bouncy balls with 500 balls are sold to stores for $75.00. One store sells them to customers for 35 cents each. What is

Contact [7]

Answer:

.20

Step-by-step explanation:

75/500 = .15

35-15=20

3 0

1 year ago

You estimated the average rental cost of a 2 bedroom apartment in Denton. A random sample of 16 apartments was taken. The sample

Zigmanuir [339]

Answer:

The new sample size required in order to have the same confidence 95% and reduce the margin of erro to $60 is:

n=28

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma=160)$

And the distribution for $\bar X$ is:

$\bar X \sim N(\mu, \frac{160}{\sqrt{n}})$

We know that the margin of error for a confidence interval is given by:

$Me=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The next step would be find the value of $\z_{\alpha/2}$ , $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$

Using the normal standard table, excel or a calculator we see that:

$z_{\alpha/2}=\pm 1.96$

If we solve for n from formula (1) we got:

$\sqrt{n}=\frac{z_{\alpha/2} \sigma}{Me}$

$n=(\frac{z_{\alpha/2} \sigma}{Me})^2$

And we have everything to replace into the formula:

$n=(\frac{1.96(160)}{78.4})^2 =16$

And this value agrees with the sample size given.

For the case of the problem we ar einterested on Me= $60, and we need to find the new sample size required to mantain the confidence level at 95%. We know that n is given by this formula:

$n=(\frac{z_{\alpha/2} \sigma}{Me})^2$

And now we can replace the new value of Me and see what we got, like this:

$n=(\frac{1.96*160}{60})^2 =27.32$

And if we round up the answer we see that the value of n to ensure the margin of error required $Me=\pm 60$ $ is n=28.

5 0

2 years ago

hayden bought 48 new trading cards three fourths of the new cards are baseball cards how many baseball cards did hayden buy

satela [25.4K]

He bought 36 baseball cards. Since 3/4 of the 48 cards are baseball cards, you need to find 75% of 48, which is 75*48, which is 36 cards. Hope this helps.

8 0

2 years ago

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