mark must leave it for 5.5 months or 5 and half moths to gain 5600 in interest .
<u>Step-by-step explanation:</u>
Here we have , mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8%. if he leaves the money in the accounts for the same length of time, We need to find how long must he leave it to gain 5600 in interest . Let's find out:
Let mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8% for time x months , So total interest gain is 5600 i.e.
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Therefore , mark must leave it for 5.5 months or 5 and half moths to gain 5600 in interest .
Answer:
P(x) = 45/100 = 0.45
Mean sample distribution = probability x number sampled by the survey.
Mean sample distribution = 0.45 x 800 = 360.00 to two decimal places.
Step-by-step explanation:
Convert the percentage to decimal probability.
45%. P(x) = 45/100 = 0.45
If there are ranges of probability values, we construct a probability distribution table. This is not necessary in the case of one probability value(45%)
Multiply the probability by the number adults to be surveyed on whether they have received phishing emails.
0.45 x 800 = 360.
Here, we assume that the 45% recorded by 2005 data, is still valid for the recent trends.
Answer:
3/4Ib = 12 ounces!
Step-by-step explanation:
hoped this helped :)
The inequality would be 3.1h + 2.3b ≥100
Step-by-step explanation:
Earning of Tammy for each hour of work= $3.1
Total hours she worked= h
Earning for picking each bushel of apple= $2.3
Total bushel she picks= b
Her goal = minimum of $100
Hence total earning from working= earning from each hour* no of hours worked
Total earning= 3.1h
Similarly, total earning from picking up apple bushels= earning from picking one bushel*no of bushels picked
Total earning= 2.3b
According to question total earning must be greater than $100
Hence, 3.1h + 2.3b ≥100
