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garik1379 [7]
3 years ago
9

Does food have energy?

Physics
1 answer:
FinnZ [79.3K]3 years ago
4 0

Answer:

chemical energy that goes for all food actually

Explanation:

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A very flexible helium-filled balloon is released from the ground into the air at 20. ∘C. The initial volume of the balloon is 5
koban [17]

Answer:

V = 38.0 L

Explanation:

As we know that number of moles will remains conserved inside the balloon

so we will have

moles = \frac{PV}{RT}

here we have

\frac{P_1V_1}{RT_1} = \frac{P_2V_2}{RT_2}

now we have

P_1 = 760 mm Hg

P_2 = 76 mm Hg

V_1 = 5.00 L

T_1 = 20^o C = 293 K

T_2 = -50^o C = 223 K

\frac{(760mm Hg)(5L)}{R(293)} = \frac{(76mm Hg)(V)}{R(223)}

V = 38.0 L

5 0
4 years ago
Read 2 more answers
Convection Warm air rising off of the pavement
Lyrx [107]

I don't understand the question, what do you need help with? PM me and I'll help!

6 0
3 years ago
Which does a reference point provide? Check all that apply.
Alona [7]

A reference point is a point in geometry or general which is used to determine or refer to another point. In reference to this point, measurements can be done. Like, a reference point in space is used to measure distance or displacement to another point. A reference point in time is used to measure the time interval of an event. A reference in space-time can be used to measure the speed or detect object's motion. Hence, the following points apply:

→A position from which to measure future distance  

→a set of standard units for measuring displacement  

→a method for determining the speed of an object  

→a way to detect an object’s motion


A reference point provides a way/method to infer information about the object.


6 0
3 years ago
Read 2 more answers
How much force is required to accelerate a 50 kg mass at 2 m/s2?
-BARSIC- [3]
=0.5 x40 
<span>= (calculate it) </span>
<span>2. F= -.45 x 41 </span>
<span>= </span>
<span>3. F=20 x 12 </span>
<span>= </span>
<span>4. F=50 x 30 </span>
<span>= </span>

<span>I believe you can go on from here, remember its easy </span>

<span>for the last 2 just rearange the formual </span>
<span>for 9 it will be a=F/m and 10. m=f/a </span>
4 0
4 years ago
A car's bumper is designed to withstand a 6.84 km/h (1.9-m/s) collision with an immovable object without damage to the body of t
PilotLPTM [1.2K]

Answer:

859.07 N

Explanation:

u = Initial velocity = 1.9 m/s

v = Final velocity

s = Displacement = 0.165 m

a = Acceleration

m = Mass = 890 kg

Equation of motion

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-1.9^2}{2\times 0.165}\\\Rightarrow a=-10.93\ m/s^2

Force

F=ma\\\Rightarrow F=870\times -10.93\\\Rightarrow F=859.07\ N

The magnitude of the average force on the bumper is 859.07 N

4 0
3 years ago
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