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3 years ago

How to find angular velocity from linear velocity and radius.

Physics

1 answer:

Lilit [14]3 years ago

6 0

Answer:

ω=v/r.

Explanation:

<em><u>angular velocity= linear velocity/radius</u></em>

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A wooden disk of mass m and radius r has a string of negligible mass is wrapped around it. If the disk is allowed to fall and th

Tju [1.3M]

Answer:

$a = \frac{2}{3}g$

$T = \frac{mg}{3}$

Explanation:

As the disc is unrolling from the thread then at any moment of the time

We have force equation as

$mg - T = ma$

also by torque equation we can say

$TR = I\alpha$

$TR = \frac{1}{2}mR^2(\frac{a}{R})$

$T = \frac{1}{2}ma$

Now we have

$mg - \frac{1}{2}ma = ma$

$mg = \frac{3}{2}ma$

$a = \frac{2}{3}g$

Also from above equation the tension force in the string is

$T = \frac{1}{2}ma$

$T = \frac{mg}{3}$

7 0

4 years ago

Which two factors affect the size of the gravitational field?

aliina [53]

Answer:

Explanation:

mass and distance

8 0

3 years ago

Which organisms were first responsible for depleting carbon dioxide from the atmosphere, replacing it with oxygen?

fgiga [73]

C) Cyanobacteria is the answer

6 0

3 years ago

Read 2 more answers

The diagram shows a ball resting at the top of a hill.

WARRIOR [948]

Answer:

a) The potential energy in the system is greatest at X.

Explanation:

Let be X the point where a ball rests at the top of a hill. By applying the Principle of Energy Conservation, the total energy in the physical system remains constant and gravitational potential energy at the top of the hill is equal to the sum of kinetic energy, a lower gravitational energy and dissipated work due to nonconservative forces (friction, dragging).

$U_{grav, X} = U_{grav, Y} + K_{Y} + \Delta W_{X \rightarrow Y} = U_{grav,Z}+\Delta W_{X \rightarrow Z}$

Conclusions are showed as follows:

a) The potential energy in the system is greatest at X.

b) The kinetic energy is the lowest at X and Z.

c) Total energy remains constant as the ball moves from X to Y.

Hence, the correct answer is A.

7 0

3 years ago

Read 2 more answers

You illuminate a slit with a width of 71.7 μm with a light of wavelength 737 nm and observe the resulting diffraction pattern on

miskamm [114]

To solve this problem we will apply the concepts related to the double slit-experiment. Under this concept we understand the relationship between the minimum angle, depending on the order of the fringes, the wavelength and the distance between slits. Therefore we have the following relation,

$sin(\theta_{min}) = \frac{m\lambda}{D}$

Here,

m = Order of the fringes

D = Distance between slits

$\lambda$ = Wavelength

Replacing with our values we have,

$sin(\theta_{min}) = \frac{(1)(737*10^{-9})}{71.7*10^{-6}m}$

$sin(\theta_{min}) = 0.01028$

Through the relationship between distances then we have that the basic amplification distance is given by the relationship between the distance of the slit L and the angle, then

$Y=Lsin\theta$

$Y =2.27*0.01028$

$Y =0.0233m$

Thus the width of the central maximum is

$W=2Y=2*0.0233$

$W = 0.0466m$

Therefore the widht is 0.466m

6 0

4 years ago