Answer:
  avriage force F = 2722.5 N
Explanation:
For this problem we can use Newton's second law, to calculate the average force and acceleration we can find it by kinematics.
       vf² = v₀² - 2 ax
The final carriage speed is zero (vf = 0)
       0 = v₀² - 2ax
       a = v₀² / 2x
       a = 1.1²/(2 0.200)
       a = 3.025 m / s²
       a = 3.0 m/s²
We calculate the average force
       F = ma
       F = 900 3,025
       F = 2722.5 N
 
        
             
        
        
        
Answer:
a) (0, -33, 12)
b) area of the triangle : 17.55 units of area 
Explanation:
<h2>
a) </h2>
We know that the cross product of linearly independent vectors  and
 and  gives us a nonzero, orthogonal to both, vector. So, if we can find two linearly independent vectors on the plane through the points P, Q, and R, we can use the cross product to obtain the answer to point a.
 gives us a nonzero, orthogonal to both, vector. So, if we can find two linearly independent vectors on the plane through the points P, Q, and R, we can use the cross product to obtain the answer to point a. 
Luckily for us, we know that vectors  and
 and  are living in the plane through the points P, Q, and R, and are linearly independent.
 are living in the plane through the points P, Q, and R, and are linearly independent.
We know that they are linearly independent, cause to have one, and only one, plane through points P Q and R, this points must be linearly independent (as the dimension of a plane subspace is 3).
If they weren't linearly independent, we will obtain vector zero as the result of the cross product.
So, for our problem:







<h2>B)</h2>
We know that  and
 and  are two sides of the triangle, and we also know that we can use the magnitude of the cross product to find the area of the triangle:
 are two sides of the triangle, and we also know that we can use the magnitude of the cross product to find the area of the triangle:

so:




 
        
             
        
        
        
Hello!
Let's begin by doing a summation of torques, placing the pivot point at the attachment point of the rod to the wall. 

We have two torques acting on the rod:
- Force of gravity at the center of mass (d = 0.700 m)
- VERTICAL component of the tension at a distance of 'L' (L = 2.200 m) 
Both of these act in opposite directions. Let's use the equation for torque:

Doing the summation using their respective lever arms:


Our unknown is 'theta' - the angle the string forms with the rod. Let's use right triangle trig to solve: 

Now, let's solve for 'T'. 

Plugging in the values:

 
        
             
        
        
        
- Total displacement=825m
- Total Time=118s
Average Velocity=Total Displacement/Total Time


 
        
             
        
        
        
Answer:
0.75 A
Explanation:
An electric current is a flow of charged particles.
A current is defined through its intensity, which is given by:

where
I is the current intensity
q is the charge passing through a given point in the circuit
t is the time it takes for the charge q to pass that point in the circuit
In this problem, we have:
q = 45 C is the charge passing through the point in the circuit
 is the time elapsed
 is the time elapsed
Therefore, the current intensity is:
