Answer:
Is there a link or image that shows us the mid segment?
Step-by-step explanation:
Two strings are 15 inches and 7 inches long.
You could draw a diagram that has two rulers (that are longer than 12 inches).
Draw a piece of string that is exactly 15 inches on one ruler.
Draw another piece of string on the other ruler at exactly 7 inches.
Then you can find the total length of the two strings by adding 15 and 7 inches.
15 + 7 = 22
The total length of both the strings is 22 inches. You can draw a ruler and a piece of string on it at 22 inches.
Please excuse my dear aunt sally ( parentheses, exponents, multiplication, division, addition, and subtraction )


7) You have the opposite. You need the adjacent.



x = 7.79289... =
<h2>7.8</h2><h2 />
8) You have the hypotenuse. You need the Opposite.


x = sin37 × 13
x = 7.8235... =
<h2>7.8</h2><h2 />
9) You have the hypotenuse. You need the opposite.


x = sin59 × 11
x = 9.4288.... =
<h2>9.4</h2><h2 />
10) You have the hypotenuse. You need the opposite.


x = sin53 × 11
x = 8.7459.... =
<h2>8.7</h2>
In exact form it would be 4/3