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almond37 [142]
3 years ago
9

The following blank indicates a missing operation in the equation.

Mathematics
1 answer:
Natalija [7]3 years ago
3 0
The answer would be 5/2q+9r+6r-20s

Explanation
We have the equation
5(1/2q+3r-4s)
which would equal
5/2q+15r-20s

so with the information
We can subtract 6r from 15r to get 9r
15r-6r=9r
+9r would be the missing piece

So we substitute it in to make the equation true.
5/2q(+9r)+6r-20s
Hope this helps or was correct
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Triangle X Y Z is shown. The length of X Y is 9, the length of Y Z is 19, and the length of X Z is y. Angle X Y Z is 41 degrees.
nalin [4]

Answer:

y² = 9² + 19² - 2(9)(19)Cos (41°)

Step-by-step explanation:

Triangle X Y Z is shown.

The length of X Y is 9,

the length of Y Z is 19, and the length of X Z is y. Angle X Y Z is 41 degrees.

Law of cosines is given as:a²= b² + c² – 2bccos(A)

Applying this to Triangle XYZ, and since we are Solving for y

y² = x² + z² - 2xzCos Y

The length of X Y = x is 9,

the length of Y Z = y is 19

y²= 9² + 19² - 2(9 × 19)Cos (41°)

= y² = 9² + 19² - 2(9)(19)Cos (41°)

Option d is correct

6 0
3 years ago
Read 2 more answers
Nine is 15% of what number
rjkz [21]

Answer:

60

Step-by-step explanation:

9/15 = 0.6

0.6 x 100 = 60

7 0
3 years ago
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Given f(x) = 3x-1 and g(x) = 2x-3 , which value of x does g(x) = f(2)
oksano4ka [1.4K]

f(2) = 6 - 1 = 5 \\ g(x) = 5 \\ 2x - 3 = 5 >  > x = 4
5 0
4 years ago
This question is worth 20 points !!!
kolbaska11 [484]

Answer:

A

Step-by-step explanation:

give me da 20 pointssss

6 0
3 years ago
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Solve the system by substitution. − x − y − z = − 8 − 4 x + 4 y + 5 z = 7 2 x + 2 z = 4
LekaFEV [45]

Answer:

The answer to your question is:

x = 3

y = 6

z = - 1

Step-by-step explanation:

                                              - x - y - z = - 8      (I)

                                         - 4x + 4y + 5z = 7     (II)

                                                   2x + 2z = 4     (III)

                                                   2z = 4 - 2x

                                                     z = 2 - x       (IIIA)

Substitute IIIA in I

- x - y - (2 - x) = - 8      - x - y - 2 + x = -8      - y - 2 = -8      - y = -8 + 2   y = 6

Substitute IIIA and y in II

                                         - 4x + 4(6) + 5(2 - x) = 7  

                                           -4x + 24 + 10 - 5x = 7

                                          -9x = 7 -34

                                          -9x = -27

                                          x = 3

Substitute x in IIIA

                                                z = 2 - 3

                                                z = - 1                    

                                     

7 0
3 years ago
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