Consider the probability that at least 93 out of 154 CDs will not be defective. Assume the probability that a given CD will not
be defective is 61%.
Approximate the probability using the normal distribution. Round your answer to four decimal places.
1 answer:
Answer:
0.5962
Step-by-step explanation:
Given that :
p = 61% = 0.61
q = 1 - p = 1 - 0.61 = 0.39
n = 154 ; x = 93
Using the binomial probability formula :
P(x =x) = nCx * p^x * (1 - p)^(n - x)
P(x>=93) = p(x=93)+p(x=94)+...+p(x=n)
P(x>= 93) = 0.59619
P(x>= 93) = 0.5962
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