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Montano1993 [528]
2 years ago
13

These two plzz:) I RLLY NEeD HE:LP

Mathematics
2 answers:
ANTONII [103]2 years ago
8 0

Answer:

10. p-0.2p

11. 0.2p

.........................

Katen [24]2 years ago
7 0

Answer:

I think its A and B

Step-by-step explanation:

Hope this helps.

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An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than
Sedbober [7]

Testing the hypothesis, it is found that:

a)

The null hypothesis is: H_0: \mu \leq 10

The alternative hypothesis is: H_1: \mu > 10

b)

The critical value is: t_c = 1.74

The decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

c)

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of <u>at most 10 pounds</u>, that is:

H_0: \mu \leq 10

At the alternative hypothesis, it is tested if the mean loss is of <u>more than 10 pounds</u>, that is:

H_1: \mu > 10

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a <u>significance level of 0.05</u> and 18 - 1 = <u>17 df.</u>

Hence, using a calculator for the t-distribution, the critical value is: t_c = 1.74.

Hence, the decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

Item c:

We have the <u>standard deviation for the sample</u>, hence the t-distribution is used. The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

For this problem, we have that:

\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18

Thus, the value of the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}

t = 1.41

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

3 0
2 years ago
A light bulb consumes 960 watt-hours per day. How many watt-hours does it consume in 3 days and 18 hours?
oksano4ka [1.4K]

960 x 3 = 2880

18/24 = 0.75

960x 0.75 = 720

2880 + 720 = 3600

7 0
3 years ago
Read 2 more answers
The volume of a cone is 16x cubic inches, Its height is 12 inches. What is the radius of the cone?
Dimas [21]
The radius would be 2
4 0
3 years ago
What is the mean absolute deviation for the set of data below?<br><br> 2, 8, 10, 16
Evgesh-ka [11]

Solution: We are given below data:

2, 8, 10, 16

Now to find the mean deviation, we use the below formula:

MD= \frac{\sum|X-\bar{X}|}{N}

Where:

\sum,  represents the summation

X, represents the observation.

\bar{X}, represents the mean

N represents the number of observation.

\bar{X}= \frac{\sum{X}}{N}= \frac{2+8+10+16}{4}=9

\sum |X-\bar{X}| = |2-9| + |8-9| +|10-9| +|16-9|=7+1+1+7=16

Therefore, the mean deviation is:

MD= \frac{16}{4}

        = 4

5 0
3 years ago
Read 2 more answers
Rewrite the expression as a single logarithm: <br> log 5 - log 7
Lady bird [3.3K]

Answer:

-0.146

Step-by-step explanation:

log 5 = 0.699

log 7 = 0.845

5 0
2 years ago
Read 2 more answers
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