No. the first 3 is 300, the second 3 is 30, and the third 3 is 3
Answer:
49/8 is the value of k
Step-by-step explanation:
We have the system
x = -2y^2 - 3y + 5
x=k
We want to find k such that the system intersects once.
If we substitute the second into the first giving us k=-2y^2-3y+5 we should see we have a quadratic equation in terms of variable y.
This equation has one solution when it's discriminant is 0.
Let's first rewrite the equation in standard form.
Subtracting k on both sides gives
0=-2y^2-3y+5-k
The discriminant can be found by evaluating
b^2-4ac.
Upon comparing 0=-2y^2-3y+5-k to 0=ax^2+bx+c, we see that
a=-2, b=-3, and c=5-k.
So we want to solve the following equation for k:
(-3)^2-4(-2)(5-k)=0
9+8(5-k)=0
Distribute:
9+40-8k=0
49-8k=0
Add 8k on both sides:
49=8k
Divide both sides by 8"
49/8=k
It totally depends on the value of 'a', and if 'a' changes, then (6a-2) immediately changes too. Whatever 'a' is at the moment, (6a-2) is 2 less than 6 times 'a'.
6 + m/4 = 3 (subtract 6 from both sides)
m/4 = -3 (multiply both sides by 4)
m = -12
Can plug in to original equation to check work:
6 - 12/4 = 3
6 - 3 = 3
3 = 3
The answer m = -12 checks out
Answer:
y= 2x +7
Step-by-step explanation:
<u>Slope-intercept</u><u> </u><u>form</u><u>:</u>
y= mx +c, where m is the slope and c is the y-intercept.
Given that the slope is 2, m=2.
y= 2x +c
Given that the y-intercept is -7, c = -7.
y= 2x +7
