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tankabanditka [31]
3 years ago
5

I have 5 dogs and 3 puppies what percent are puppies

Mathematics
2 answers:
nikitadnepr [17]3 years ago
8 0

Answer:

Welcome to brainly :) yur answer is 24%

Step-by-step explanation:

5+3=8

3% of 8= 24%

romanna [79]3 years ago
6 0
5+3 = 8
8 is 100%
3/8 = 37.5%
I feel like I might be wrong haha sorry if I am
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Jose surveyed the length of TV commercials (in seconds). Find, to 3 decimal places, the experimental probability that a randomly
Lynna [10]

Answer:

≈0.487

Step-by-step explanation:

I think this is your full question right?

Jose surveyed the length of TV commercials (in seconds). Find, to 3 decimal places, the experimental probability that a randomly chosen TV commercial will last:

Length        Frequency

0-19                   17

20-39               38

40-59                19                    20 to 39 seconds.

60+ 20 to          4

Here is my anwer:

experimental probability = relative frequency = \frac{number of oserved occuerencies}{total number of oserved occuerencies}

Total frequencies = 17 + 38 +18 + 4 = 78

P(20 to 39s) = 38/78 ≈0.487  

6 0
3 years ago
Raylan opened a savings account with $100. After 5 years there is $122. 50 in the account. What is his simple interest rate?
serious [3.7K]
<h3>Answer:</h3>

4.5% annually

<h3>Step-by-step explanation:</h3>

Simple interest is the amount of interest added to a singular sum of money at a fixed rate.

Formula

The formula for simple interest is A = P(1+rt). In this formula, A is the total amount of money in the account, P is the original amount deposited, r is the rate of interest as a decimal, and t is the time in years.

Calculations

To find the rate, plug the information we know into the formula above

  • 122.50 = 100(1+r*5)

Divide both sides by 100

  • 1.225 = 1 + r*5

Subtract 1 from both sides

  • 0.225 = r*5

Divide both sides by 5

  • 0.045 = r

This gives us the rate as a decimal. So, to find the rate as a percent. Do this by moving the decimal 2 places to the right (or just multiply by 100, they do the same thing). This means that the rate of simple interest is 4.5%.

5 0
2 years ago
50 Points and brainliest, simple data
Masja [62]
14 | 7 | 21
6 | 3 | 9
20 |10| 30

i hope you understand how im trying to put i
7 0
2 years ago
Use this list of Basic Taylor Series and the identity sin2θ= 1 2 (1−cos(2θ)) to find the Taylor Series for f(x) = sin2(3x) based
notsponge [240]

Answer:

The Taylor series for sin^2(3 x) = - \sum_{n=1}^{\infty} \frac{-9^{n}2^{2n-1}x^{2n}}{(2n)!}, the first three non-zero terms are 9x^{2} -27x^{4}+\frac{162}{5}x^{6} and the interval of convergence is ( -\infty, \infty )

Step-by-step explanation:

<u>These are the steps to find the Taylor series for the function</u> sin^2(3 x)

  1. Use the trigonometric identity:

sin^{2}(x)=\frac{1}{2}*(1-cos(2x))\\ sin^{2}(3x)=\frac{1}{2}*(1-cos(2(3x)))\\ sin^{2}(3x)=\frac{1}{2}*(1-cos(6x))

   2. The Taylor series of cos(x)

cos(y) = \sum_{n=0}^{\infty}\frac{-1^{n}y^{2n}}{(2n)!}

Substituting y=6x we have:

cos(6x) = \sum_{n=0}^{\infty}\frac{-1^{n}6^{2n}x^{2n}}{(2n)!}

   3. Find the Taylor series for sin^2(3x)

sin^{2}(3x)=\frac{1}{2}*(1-cos(6x)) (1)

cos(6x) = \sum_{n=0}^{\infty}\frac{-1^{n}6^{2n}x^{2n}}{(2n)!} (2)

Substituting (2) in (1) we have:

\frac{1}{2} (1-\sum_{n=0}^{\infty}\frac{-1^{n}6^{2n}x^{2n}}{(2n)!})\\ \frac{1}{2}-\frac{1}{2} \sum_{n=0}^{\infty}\frac{-1^{n}6^{2n}x^{2n}}{(2n)!}

Bring the factor \frac{1}{2} inside the sum

\frac{6^{2n}}{2}=9^{n}2^{2n-1} \\ (-1^{n})(9^{n})=(-9^{n} )

\frac{1}{2}-\sum_{n=0}^{\infty}\frac{-9^{n}2^{2n-1}x^{2n}}{(2n)!}

Extract the term for n=0 from the sum:

\frac{1}{2}-\sum_{n=0}^{0}\frac{-9^{0}2^{2*0-1}x^{2*0}}{(2*0)!}-\sum_{n=1}^{\infty}\frac{-9^{n}2^{2n-1}x^{2n}}{(2n)!}\\ \frac{1}{2} -\frac{1}{2} -\sum_{n=1}^{\infty}\frac{-9^{n}2^{2n-1}x^{2n}}{(2n)!}\\ 0-\sum_{n=1}^{\infty}\frac{-9^{n}2^{2n-1}x^{2n}}{(2n)!}\\ sin^{2}(3x)=-\sum_{n=1}^{\infty}\frac{-9^{n}2^{2n-1}x^{2n}}{(2n)!}

<u>To find the first three non-zero terms you need to replace n=3 into the sum</u>

sin^{2}(3x)=\sum_{n=1}^{\infty}\frac{-9^{n}2^{2n-1}x^{2n}}{(2n)!}\\ \sum_{n=1}^{3}\frac{-9^{3}2^{2*3-1}x^{2*3}}{(2*3)!} = 9x^{2} -27x^{4}+\frac{162}{5}x^{6}

<u>To find the interval on which the series converges you need to use the Ratio Test that says</u>

For the power series centered at x=a

P(x)=C_{0}+C_{1}(x-a)+C_{2}(x-a)^{2}+...+ C_{n}(x-a)^{n}+...,

suppose that \lim_{n \to \infty} |\frac{C_{n}}{C_{n+1}}| = R.. Then

  • If R=\infty, the the series converges for all x
  • If 0 then the series converges for all |x-a|
  • If R=0, the the series converges only for x=a

So we need to evaluate this limit:

\lim_{n \to \infty} |\frac{\frac{-9^{n}2^{2n-1}x^{2n}}{(2n)!}}{\frac{-9^{n+1}2^{2*(n+1)-1}x^{2*(n+1)}}{(2*(2n+1))!}} |

Simplifying we have:

\lim_{n \to \infty} |-\frac{(n+1)(2n+1)}{18x^{2} } |

Next we need to evaluate the limit

\lim_{n \to \infty} |-\frac{(n+1)(2n+1)}{18x^{2} } |\\ \frac{1}{18x^{2} } \lim_{n \to \infty} |-(n+1)(2n+1)}|}

-(n+1)(2n+1) is negative when n -> ∞. Therefore |-(n+1)(2n+1)}|=2n^{2}+3n+1

You can use this infinity property \lim_{x \to \infty} (ax^{n}+...+bx+c) = \infty when a>0 and n is even. So

\lim_{n \to \infty} |-\frac{(n+1)(2n+1)}{18x^{2} } | \\ \frac{1}{18x^{2}} \lim_{n \to \infty} 2n^{2}+3n+1=\infty

Because this limit is ∞ the radius of converge is ∞ and the interval of converge is ( -\infty, \infty ).

6 0
3 years ago
ILL MARK BRAINLIST Which of the following data sets is represented in the dot plot?
arlik [135]

Answer:

1'3'5'4

Step-by-step explanation:

7 0
4 years ago
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