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ASHA 777 [7]
3 years ago
6

Question 9

Chemistry
1 answer:
jekas [21]3 years ago
4 0

Answer:

hi

Explanation:

I'm just figuring this out

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What is an example of a scope three carbon emission?
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Production of materials and transportation are the examples of three carbon emission.

Extraction and production of purchased materials and transportation of purchased fuels are the examples of three carbon emission. Scope 3 emissions refers to all indirect emissions that occur in the chain of the reporting company that is included in both upstream and downstream emissions.

Big machineries are used for the production and extraction of materials as well as the transportation requires fossil fuels for working which releases carbondioxide gas in the atmosphere so we can conclude that production of materials and transportation are the examples of three carbon emission.

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Given: glow is a find the indicated measure.​
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Explanation:

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CAN YALL PLEASE HELP?!?!
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I don’t really know but Yk how they are categorized by color try checking the atomic levels or some around that hope I was some type of help
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Describe the main properties of a gas. check all that apply
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Gases have three characteristic properties: (1) they are easy to compress, (2) they expand to fill their containers, and (3) they occupy far more space than the liquids or solids from which they form.
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3 years ago
Read 2 more answers
. The Henry's law constant for helium gas in water at 30 ∘C is 3.7×10−4M/atm; the constant for N2 at 30 ∘C is 6.0×10−4M/atm. a.
ludmilkaskok [199]

Explanation:

1) Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

M_{g}=K_H\times p_{g}

where,

K_H = Henry's constant

p_{He} = partial pressure of gas

a)  K_H=3.7\times 10^{-4} M/atm

p_{He}=2.1 atm

Putting values in above equation, we get:

M_{He}=3.7\times 10^{-4} M/atm\times 2.1 atm = 7.77\times 10^{-4} M

The solubility of helium gas is 7.77\times 10^{-4} M

b)  K_H=6.0\times 10^{-4} M/atm

p_{N_2}=2.1 atm

Putting values in above equation, we get:

M_{He}=6.0\times 10^{-4} M/atm\times 2.1 atm = 1.26\times 10^{-3} M

The solubility of nitrogen gas is 1.26\times 10^{-3} M

2)

a) Mass of solute or methanol , m= 14.7 g

Mass of solvent or water , m'= 186 g

Mass of the solution = M = m + m' = 14.7 g + 186 g = 200.7 g

w/w\%=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100

=\frac{14.7 g}{200.7 g}\times 100=7.32\%

The mass percent of methanol is 7.32%.

b) Molality is defined as moles of solute per kilograms of solvent.

m=\frac{\text{Moles of solute}}{\text{Mass of solvent in kg}}

Moles of methanol = \frac{14.7 g}{32 g/mol}=0.4594 mol

Mass of solvent = 186 g = 0.186 kg

m=\frac{0.4594 mol}{0.186 kg}=2.4610 mol/kg

The molality of methanol is 2.4610 mol/kg.

4 0
3 years ago
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