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STatiana [176]
3 years ago
8

1(30%). A thin plate black body, insulated at the bottom is placed faced up in a room with wall temperatures of 30 C. Air at 0 C

is forced over the plate with a convective heat transfer coefficient of 12 W/m².C. Calculate the plate temperature under steady state condition
Chemistry
1 answer:
ch4aika [34]3 years ago
3 0

Explanation:

The given data is as follows.

         Heat transfer coefficient (h) = 12W/m^{2}.C

         Plate temperature (T_{1}) = 30 ^{o}C = 303 K

         Steady state temperature (T_{2}) = ?

Hence, formula applied for steady state is as follows.

       (h \times A \times \Delta T)_{air} = \sigma \times A \times (T^{4}_{1} - T^{4}_{2})_{plate}

Putting the given values into the above formula as follows.

       (h \times A \times \Delta T)_{air} = \sigma \times A \times (T^{4}_{1} - T^{4}_{2})_{plate}

        12 \times (T_{2} - 273) = 5.67 \times 10^{-8} \times [(30 + 273)^{4} - T^{4}_{2}]

                  T_{2} = 282.66 K

                              = (282.66 -273)^{o}C      

                              = 9.66 ^{o}C      

Thus, we can conclude that the steady state temperature will be 9.66 ^{o}C.

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It is clear that every 2 mol of NH₄OH need 1 mol of H₂SO₄ to be neutralized.

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It is clear that every 1 mol of NH₄OH needs 1 mol of H₂SO₄ to be neutralized.

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2.1618 grams of P4 is required to produce 4.21x10^22 molecules of phosphorus trifluoride.

Explanation:

The balanced chemical reaction for formation of PF3 from yellow phosphorus is given by:

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1 mole of P4 reacts to give 4 moles of PF3

It is given that 4.21x10^22 molecules of PF3 are produced

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number of moles = \frac{number of molecules}{avagadro number}

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Applying stoichiometry,

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x mole will produce 0.06989 moles of PF3

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4x= 0.0698 × 1

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x= 0.01745 moles of P4 will be required.

The weight of the phosphorus can be obtained by number of moles × atomic mass of one mole of P4

= 0.01745 × 123.89

= 2.1618 grams of P4.

     

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