6 pies.
If 8 teachers finish one whole pie, and they need to feed 47, then they need 6 pies with 8 slices each aka 48 slices total, there will be one slice leftover for the principal :D
(3 + (2/3))(2+(1/2) = 3*2+2*(2/3)+3*(1/2)+((2/3)(1/2)) = 6+(4/3) +(3/2) + (2/6) = 6 + ((8+9+2)/6) = 6 + (19/6) = 6 + 3 + 1/6 = 9 + 1/6 miles = D
Answer:
JL = 78
Step-by-step explanation:
MN is a midsegment. Based on the midsegment theorem,
MN = ½(JL)
MN = 5x - 16
JL = 4x + 34
Plug in the value
5x - 16 = ½(4x + 34)
5x - 16 = ½*4x + ½*34
5x - 16 = 2x + 17
Collect like terms
5x - 2x = 16 + 17
3x = 33
Divide both sides by 3
x = 11
✔️JL = 4x + 34
Plug in the value of x
JL = 4(11) + 34
JL = 44 + 34
JL = 78
Answer:
See explaination for the details of the answer
Step-by-step explanation:
Defect per opportunity DPO = defects/ no. of opportunities = 2/25 = 0.08
Defect per million opportunities
DPMO = DPO * 1 million
DPMO = 0.08 * 1 million = 80,000
six sigma = 2.9, take the dpmo at higher level if not exact 80800 for 2.9
The original price is $4.50 because when you multiply it by 50% you get $2.25
