When you add, you subtract the exponents. When you divide, you subtract the exponents.
When you have multiplication and division in one expression, you do it from left to right.
7^2 times 7^5 = 7^ (2+5) = 7^7
7^7 times 2^2 / 7^3 = 7 ^(7 - 3) times 2^2
7^4 times 2^2 times 2^6 = 7^4 times 2^(2+6) = 7^4 times 2^8
Put it in a calculator.
614656.
That is the answer, but you didn't include the "which of the following", so I guess you'll have to put each value in the calculator to find out!
If the 7^3 times 2^6 is in parenthesis, then the answer is 150.0625.
Answer:
0.0803 = 8.03% probability that the number who have a high school degree as their highest educational level is exactly 32.
Step-by-step explanation:
For each adult, there are only two possible outcomes. Either they have a high school degree as their highest educational level, or they do not. The probability of an adult having it is independent of any other adult. This means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which 
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
30.4% of U.S. adults 25 years old or older have a high school degree as their highest educational level.
This means that 
100 such adults
This means that 
Determine the probability that the number who have a high school degree as their highest educational level is a. Exactly 32
This is P(X = 32).
0.0803 = 8.03% probability that the number who have a high school degree as their highest educational level is exactly 32.
Given parameters;
Let us solve this problem step by step;
Let us represent Simon's money by S
Kande's money by K
- Simon has more money than Kande
S > K
- if Simon gave Kande K20, they would have the same amount;
if Simon gives $20, his money will be S - 20 lesser;
When Kande receives $20, his money will increase to K + 20
S - 20 = K + 20 ------ (i)
- While if Kande gave Simon $22, Simon would then have twice as much as Kande;
if Kande gave Simon $22, his money will be K - 22
Simon's money, S + 22;
S + 22 = 2(K - 22) ------ (ii)
Now we have set up two equations, let us solve;
S - 20 = K + 20 ---- i
S + 22 = 2(K - 22) ; S + 22 = 2K - 44 ---- ii
So, S - 20 = K + 20
S + 22 = 2K - 44
subtract both equations;
-20 - 22 = (k -2k) + 64
-42 = -k + 64
k = 106
Using equation i, let us find S;
S - 20 = K + 20
S - 20 = 106 + 20
S = 106 + 20 + 20 = 146
Therefore, Kande has $106 and Simon has $146
We assume all money is spent on new lighting. Since they currently have $160 and need $400 we can subtract what they currently have from what they need.
$400-$160 = $240
Since we know the price of the ticket and now know they need $240 we can divide our $240 with the price of each ticket ($3)
$240/$3 = 80
So the drama club has to sell 80 more tickets in order to afford new lighting
