Answer: C. (-1/6)^5
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A= -8
B= -24
4*-2= -8
48/-2=-24
The probability would be 50%
Answer:
The number of ways to select a sample of 2 computer chips so that at least one of the chips is defective is 33 ways.
Step-by-step explanation:
The box contains 13 computer chips. Of these 13 chips 3 are defective and 10 are good.
A quality control inspector samples 2 computer chips.
The number of ways to select at least 1 defective chip is:
n (At least 1 defective chip) = n (1 defective chip) + n (2 defective chips)
The number of ways to select 1 defective chip is:
ways.
The number of ways to select 2 defective chips is:
ways.
n (At least 1 defective chip) = n (1 defective chip) + n (2 defective chips)
= 30 + 3
= 33
Thus, the number of ways to select a sample of 2 computer chips so that at least one of the chips is defective is 33 ways.
Answer:
P = 2/16 This is based on 14/16 chance that the next pastry will be something else.
Step-by-step explanation:
We can also expand and say P= 2/16 = 1/8
Not P= 7/8