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erastova [34]
2 years ago
7

△JKL has vertices at J(−2, 4), K(1, 6), and L(4, 4). Determine whether △JKL is a right triangle. Explain. please with full calcu

lations
Mathematics
1 answer:
KATRIN_1 [288]2 years ago
3 0

Answer:

below

Step-by-step explanation:

basically find the line that connects JK and KL, and since its 2/3 and -2/3 which are not opposite reciprocals, the points dont form a right triangle

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#8 HELP IM STUCK ON THIS
jeka57 [31]

Answer:

12 ft

Step-by-step explanation:

for the model is 1 and the actual is 5

conversion yards to feet

3 feet = 1 yard

20 * 3 = 60

60/5 = 12

your answers 12 ft

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4 0
2 years ago
Which expression can be used to find 7(-6 1/8)
andrezito [222]

The first option,

both have to be negative, because they were originally both part of the one fraction, which was all negative.

7 0
2 years ago
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14 = 2y/5 what is the solution?
Gnom [1K]

Answer:

y=35

Step-by-step explanation:

y in (-oo:+oo)

14 = (2*y)/5 // - (2*y)/5

14-((2*y)/5) = 0

(-2/5)*y+14 = 0

14-2/5*y = 0 // - 14

-2/5*y = -14 // : -2/5

y = -14/(-2/5)

y = 35

y = 35

5 0
3 years ago
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Lady bird [3.3K]

Answer:

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3 years ago
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5) Find the equation of the line going through the point (4,1) and<br> perpendicular to y = - 3x +7
vovangra [49]

Answer:

3y=x-1 OR y=⅓x-⅓

Step-by-step explanation:

Lets call the equation y=-3x+7 line l1

the other line passing through (4,1) l2

If two lines are perpendicular,then the product of their roots=-1

That is m(l1)×m(l2)=-1

Slope of l1=-3 therefore slope of l2=-1÷-3=⅓

Now that we have determined the slope of l2 we move on to find it's equation using the point-slope form

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y-1=⅓(x-4)

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3y=x-4+3

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6 0
3 years ago
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