△JKL has vertices at J(−2, 4), K(1, 6), and L(4, 4). Determine whether △JKL is a right triangle. Explain. please with full calcu
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By identifying the radius and the center, we concluded that the equation is something like:
For a circle centered on the point (a, b) with a radius R, the equation is:
So first we need to identify the center, we can see that it is: (2, 1.5)
And the radius is the distance between the center and the edge.
R = 1.8 (measured with a ruler, respecting the notation of the graph).
Then the equation of the circle is something like:
If you want to learn more about circles:
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