Omg don’t catfish it’s so damaging to your own self confidence!
a) find the slope of the line using the given points.
Slope: 9 - -3/6-0 then slope is 12/6 which is 2
Then using formula: y = mx+b
-3 = 2(0) + b
b = -3
The equation is: y = 2x -3
B. Slope of a perpendicular is -reciprocal of first line. So here the slope will be -1/2
y = mx + b is used again
2 = -1/2(0) + b
b = 2
The equation is: y = -1/2x +2
the answer to your question is -12
Answer:
and as 
Step-by-step explanation:
Given
-- Missing from the question
Required
The behavior of the function around its vertical asymptote at 

Expand the numerator

Factorize

Factor out x + 1

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)
We are only interested in the sign of the result
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As x approaches -2 implies that:
Say x = -3


We have a negative value (-12); This will be called negative infinity
This implies that as x approaches -2, p(x) approaches negative infinity

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)
As x leaves -2 implies that: 
Say x = -2.1

We have a negative value (-56.1); This will be called negative infinity
This implies that as x leaves -2, p(x) approaches negative infinity

So, the behavior is:
and as 
This is 8). the line is 5 on the y-axis.