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Dmitry_Shevchenko [17]
3 years ago
10

Question above. (BRAINLY WANTS ME TO MAKE THE QUESTION 20 CHARACTERS LONG)

Mathematics
1 answer:
stepladder [879]3 years ago
7 0

Answer:

10. 32 & 37

11. 3 & 4

(っ◔◡◔)っ ♥ Hope It Helps, Please Consider giving Brainliest ♥

(P.S. if you need an explanation just ask in comments)

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Jalen had 4 2/3 pounds of modeling clay and used 3 1/2 pounds for a craft project. How many pounds of clay were not used?
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I hope this helps!

The answer would be 1 1/6

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At a store, 4 shirts cost $25 and 6 shirts cost $37.50.
Gelneren [198K]
Yes, each shirt is $6.25.
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-4|x +3| = -28<br> I can’t figure it out ):
SIZIF [17.4K]

Answer:

Step-by-step explanation:

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3 0
2 years ago
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Which is the value of this expression when a = 5 and k = negative 2?
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7 0
3 years ago
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ou find a deck of cards and know that the deck has too many clubs and spades in it. The deck has 59 cards. If you were to draw t
sashaice [31]
We can find the number of extra clubs in the deck from the given probability, since the probability of drawing a diamond and a club is

\dfrac{\binom{13}1\binom{13+c}1}{\binom{59}2}=\dfrac{13(13+c)}{1711}

but this would imply that c=-4, which suggests we're taking 4 clubs out of the original deck and contradicts the problem statement that there are "too many clubs".

Perhaps the question is providing the probability of drawing a diamond, THEN a club, or vice versa. In that case, we have

\dfrac{\binom{13}1}{\binom{59}1}\cdot\dfrac{\binom{13+c}1}{\binom{58}1}=\dfrac{13(13+c)}{3422}

and solving gives c=5, which makes more sense. Then the number of extra spades in the deck must be 2.
7 0
3 years ago
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