Sketch a graph so you can find the vertex and determine if the parabola is horizontal or vertical. When i graph (-2,4) and then y=6, I find the middle is (-2,5) so that will be the vertex. The distance to the vertex is -1 so 4p=-4.
My formula is (x-h)^2=4p(y-k), now just plug in numbers. You should end up with (x+2)^2=-4(y-5).
Some instructors want you to write (y-k)=1/(4p)(x-h)^2 which is the same thing, so check to see which one you should be using.
Answer:
<h2><em><u>m</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>6.43</u></em><em><u> </u></em><em><u>(</u></em><em><u>approx</u></em><em><u>. </u></em><em><u>)</u></em></h2>
Step-by-step explanation:
49 - 3m = 4m + 4
=> 49 - 4 = 4m + 3m
=> 45 = 7m
=> 6.428571... = m
=><em><u> m = 6.43 (approx. ) (Ans)</u></em>
Sry but that’s too much which one would you like help on
Answer:
-4, 2, 0
Step-by-step explanation:
- -2x>10
- Divide -2 and 10 by -2 to get x>-5
- Select all the numbers that are greater than -5
Answer:
Step-by-step explanation:
The x-intercept exists when y = 0; the coordinate takes on the form ( , 0)
The y-intercept exists when x = 0; the coordinate takes on the form (0, ).
We will fill in the blanks in a sec.
If the x-intercept exists when y = 0, then we fill in 0 for y and solve for x:
-3(0) - x = -9 so
-x = -9 and
x = 9
The coordinate is (9, 0) for the x-intercept.
If the y-intercept exists when x = 0, then we fill in 0 for x and solve for y:
-3y - 0 = -9 so
-3y = -9 and
y = 3
The coordinate is (0, 3) for the y-intercept.
