The volume (in mL) of calcium hydroxide, Ca(OH)₂ needed for the reaction is 19.8 mL
<h3>Balanced equation </h3>
2HCl + Ca(OH)₂ —> CaCl₂ + 2H₂O
From the balanced equation above,
- The mole ratio of the acid, HCl (nA) = 2
- The mole ratio of the base, Ca(OH)₂ (nB) = 1
<h3>How to determine the volume of Ca(OH)₂ </h3>
- Molarity of base, Ca(OH)₂ (Mb) = 1.48 M
- Volume of acid, HCl (Va) = 36 mL
- Molarity of acid, HCl (Ma) = 1.63 M
- Volume of base, Ca(OH)₂ (Vb) =?
MaVa / MbVb = nA / nB
(1.63 × 36) / (1.48 × Vb) = 2
58.68 / (1.48 × Vb) = 2
Cross multiply
2 × 1.48 × Vb = 58.68
2.96 × Vb = 58.68
Divide both side by 2.96
Vb = 58.68 / 2.96
Vb = 19.8 mL
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Answer:
There are 17.64% students received B+ grades.
Explanation:
It is given that,
Total number of students in chemistry class is 17
We need to find the percentage received by B+.
Number of students having B+ grades are 3 (from graph)
Required percentage = 
So, there are 17.64% students received B+ grades.
Answer: The answer would be 4. Carbon dioxide : deforestation
Explanation:
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Answer:
The temperature of the nitrogen gas at another section is 
Explanation:
Energy balance equation for steady state flow of gas under negiligible potential energy.
The negligible heat transfer and no shaft work is as follows.


is enthalphy of gas and it is changes with the temperature.

= Molar heat capacity of the gas at constant pressure.
= Initial temperature at section 1
= Final temperature at section 2
Substitute the equation (2) in equation (1)

Solve the above equation is as follows.

From the given,




Molar mass of nitrogen gas = 0.02802 kg/mol
Substitute the all values in the equation (3)

=421.8K=148.8^{o}C
Therefore,The temperature of the nitrogen gas at another section is
.