<span>Answer:
We heated up the liquid CFC from 11.05 degrees celsius to its boiling point (47.6 degrees)
That means we heated it up 36.55 degrees
The formula to solve this is C = Q / M x dT
where
C is the specific heat of the liquid CFC (.91 J/G/C)
Q is the amount of heat required (what we're trying to find out)
M is the mass (52.5 grams)
and dT is the temperature difference (36.55 degrees)
Now put in the values and find out what Q is
.91 = Q / 52.5 x 36.55
.91 = Q / 1918.875
Q = 1746.17 joules to heat up the liquid CFC</span>
Answer:
H₃O⁺.
Explanation:
- When H⁺ is bonded to water molecule, it forms hydronium ion:
<em>H⁺ + H₂O → H₃O⁺.</em>
The change in heat is simply equal to:
change in heat ΔH = final enthalpy – initial enthalpy
ΔH = [280.25 g * 4.18J/gC * (17.5°C)] – [280 g * 4.18J/gC
* 13.5°C]
ΔH = 4,699.89 J = 4.7 kJ
<span>Hence heat released is about 4.7 kJ</span>
Answer:
By the Pauling rule, of EN
Explanation:
EN means electronegativity, the ability of atoms to attract electrons.
In the periodic table each atom, has a value of EN.
When there are two atoms bonded, you must substract the EN (the high - the low) → ΔEN
It depends on the ΔEN, that you can define a bond as ionic, covalent or metallic.
Ionic ΔEN → > 1.7
Covalent polar 0.4 < ΔEN > 1.7
Covalent non polar 0.4 < ΔEN
Two metals have always a metallic bond
