Chicago is about 2,800 km from Los Angeles. About how long would it take a jet plane flying 800 km/h to fly from Chicago to Los
1 answer:
<u>Answer:</u> The time taken by jet plane to reach Los Angeles from Chicago is 3.5 hours
<u>Explanation:</u>
Speed is defined as the rate at which an object moves with respect to time.
To calculate the time taken for the given speed, we use the equation:
where,
s = speed of the jet plane = 800 km/hr
d = distance traveled = 2800 km
t = time taken by jet plane = ?
Putting values in above equation, we get:
Hence, the time taken by jet plane to reach Los Angeles from Chicago is 3.5 hours
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Answer:- oxygen.
Explanations:- The electronic configuration is given and we are asked to figure out the electrically neutral atom that will have the electron configuration, .
The sum of electrons for this electron configuration is 8. If we look at the periodic table then 8 is the atomic number of oxygen.
So, the electrically neutral atom for the given electron configuration is oxygen.
Answer:
The molar mass of unknown β‑Galactosidaseis 116,352.97 g/mol.
Explanation:
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:
where,
= osmotic pressure of the solution = 0.602 mbar = 0.000602 bar
0.000602 bar = 0.000594 atm
(1 atm = 1.01325 bar)
i = Van't hoff factor = 1 (for non-electrolytes)
c = concentration of solute = ?
R = Gas constant =
T = temperature of the solution =
Putting values in above equation, we get:
The concentration of solute is
Volume of the solution = V =0.137 L
Moles of β‑Galactosidase = n
To calculate the molecular mass of solute, we use the equation:
Moles of β‑Galactosidase =
Given mass of β‑Galactosidase= 0.387 g
Putting values in above equation, we get:
Hence, the molar mass of unknown β‑Galactosidaseis 116,352.97 g/mol.
126 grams of H2O is formed.
Explanation:
Data given:
volume of the gas = 88 Liters
pressure = 720 mm Hg or 0.947 atm
temperature T = 22 Degrees or 295.15 K
R = 0.08021 atm L/mole K
n =?
The formula is used is of ideal gas law to know the number of moles of CH4 undergoing combustion.
PV = nRT
n =
putting the values in the equation
= 0.947 X 88/ 0.08021 X 295.15
n = 3.5 moles
balanced reaction for combustion of methane
CH4 + O2 ⇒ CO2 + 2H20
1 mole of CH4 undergoes combustion to form 2 moles of water
3.5 moles will give x moles of water
2/1 = x/3.5
x = 7 moles of water (atomic mass of water = 18 gram/mole)
mass = atomic mass x number of moles
mass = 18 x 7
=126 grams of water is formed.