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alexdok [17]
3 years ago
10

Bob measured out 1.60 grams of sodium. He calculates that 1.60 g of

Chemistry
1 answer:
saul85 [17]3 years ago
6 0

Answer:

84.8%

Explanation:

Step 1: Given data

Bob measured out 1.60 g of Na. He forms NaCl according to the following equation.

Na + 1/2 Cl₂ ⇒ NaCl

According to this equation, he calculates that 1.60 g of sodium should produce 4.07 g of NaCl, which is the theoretical yield. However, he carries out the experiment and only makes 3.45 g of NaCl, which is the real yield.

Step 2: Calculate the percent yield.

We will use the following expression.

%yield = real yield / theoretical yield × 100%

%yield = 3.45 g / 4.07 g × 100% = 84.8%

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Which scientist performed the cathode ray experiment leading to the discovery of electrons
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The scientist that performed the cathode ray experiment leading to the discovery of electrons is J.J. Thomson.

<h3>What is a cathode ray?</h3>

A cathode ray is a tube that contains negatively charged electrode( that is the cathode) which emits electrons when heated at a low pressure.

The cathode ray was used by the scientist, J.J. Thomson to find the ratio of charge to mass (e/m) of the electrons.

Therefore, the scientist that performed the cathode ray experiment leading to the discovery of electrons is J.J. Thomson.

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2 years ago
What mass of copper is deposited when a current of 10.0a is passed through a solution of copper(ii) nitrate for 30.6 seconds?
asambeis [7]
Data Given:

Time = t = 30.6 s

Current = I = 10 A

Faradays Constant = F = 96500

Chemical equivalent = e = 63.54/2 = 31.77 g

Amount Deposited = W = ?

Solution:
             According to Faraday's Law,

                                          W  =  I t e / F

Putting Values,
 
                            W  =  (10 A × 30.6 s × 31.77 g) ÷ 96500

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Result:
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3 years ago
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Answer:

Put up the answer choices

Explanation:

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5 0
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As a result, when the situation is at the melting curve, a rise in temperature will result in a large partial melt because of the presence of water. As seen in the wet peridotite melting curves in the aforementioned curves.

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Only the peridotite's temperature changes during intraplate melting, not the pressure. Therefore, as the temperature rises, it will begin to melt Decompression causes melting at diverging boundaries. Temperature plays no part in this.

Hence, the answer is Convergent plate boundary

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