First, we need to convert the grams of gold into mole using the molar mass (molecular weight) of gold, and then into particles using avogadro's number (1 mol= 6.02 x 10^23)
molar mass of gold= 197 grams/ mole
100.0 grams (1 mole/ 197 grams) x (6.02 x 10^23 particles/ 1 mole) = 3.06 x 10^23
Answer:
mass Na2SO4 = 14.3816 g
Explanation:
sln Na2SO4:
∴ V = 450 mL
∴ <em>C </em>=<em> </em>0.2250 mol/L
∴ Mw ≡ 142.04 g/mol..... from literature
⇒ mol Na2SO4 = (0.2250 mol/L)(0.450 L) = 0.10125 mol
⇒ mass Na2SO4 = (0.10125 mol)(142.04 g/mol) = 14.3816 g
