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Stels [109]
3 years ago
9

When bar-headed geese fly at very high altitudes (possibly over Mount Everest!), they breathe very thin air where the partial pr

essure of oxygen is very low compared to that at sea level. Which of the following adaptions would help the geese efficiently exchange gases when flying at high altitudes? ______
A) hemoglobin that has a high affinity for oxygen
B) hemoglobin that has a high affinity for carbon dioxide
C) hemoglobin that has a low affinity for carbon dioxide
D) hemoglobin that has a low affinity for oxygen
Chemistry
1 answer:
Reil [10]3 years ago
5 0

Answer:hemoglobin that has a high affinity for oxygen

Explanation:

Haemoglobin is the oxygen carrying pigment in blood. It performs this function because of the presence of iron at the center of the haemoglobin which coordinates reversibly with oxygen thereby aiding delivery of oxygen to cells. At high altitudes where air is thinner and the partial pressure of oxygen is lower than sea level, haemoglobin must develop a greater affinity for oxygen in order to carry the scarce oxygen to cells.

You might be interested in
Ultraviolet radiation and radiation of shorter wavelengths can damage biological molecules because they carry enough energy to b
Alja [10]

Answer:

439.7nm

Explanation:

Energy of a quantum can be calculated using below formula

E=hv...........eqn(1)

But v=λ/ c .........eqn(2)

If we substitute eqn(2) into eqn(1) we have

E= hc/(λ)

Where E= energy

h= Plank's constant= 6.62607004 × 10-34 m2 kg / s

c= speed of light

c= 2.998 × 10^8 m/s

λ= wavelength= ?

But the energy was given in Kj , it must be converted to Kj/ photon for unit consistency.

Energy E= 272 kJ/mol × 1mol/6.02× 10^23

Energy= 451.83× 10^-24 Kj/ photon

E= hc/(λ)...........eqn(1)

If we make λ subject of the formula

λ= hc/E

Then substitute the values we have

λ= [(6.626 × 10^-34) × (2.998 × 10^8)]/451.83× 10^-24

λ=(0.00043965) × (1Kj/1000J) × (10^9nm/1m)

λ=439.7nm

Hence, the longest wavelength of radiation with enough energy to break carbon-sulfur bonds is 439.7nm

4 0
2 years ago
a concentration solution of H2so4 is 59.4% by mass (m/m) and has a density of 1.83 g/mL. How many mL of the solution would be re
Blababa [14]

Answer: 41.5 mL

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in L

Given : 59.4 g of H_2SO_4 in 100 g of solution  

moles of H_2SO_4=\frac{\text {given mass}}{\text {molar mass}}=\frac{59.4g}{98g/mol}=0.61

Volume of solution =\frac{\text {mass of solution}}{\text {density of solution}}=\frac{100g}{1.83g/ml}=54.6ml

Now put all the given values in the formula of molality, we get

Molality=\frac{0.61\times 1000}{54.6ml}=11.2M

To calculate the volume of acid, we use the equation given by neutralisation reaction:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of stock acid which is H_2SO_4

M_2\text{ and }V_2 are the molarity and volume of dilute acid which is H_2SO_4

We are given:

M_1=11.2M\\V_1=mL\\M_2=0.30M\\V_2=1550mL

Putting values in above equation, we get:

11.2\times V_1=0.30\times 1550\\\\V_1=41.5mL

Thus 41.5 mL of the solution would be required to prepare 1550 mL of a .30M solution of the acid

4 0
3 years ago
1. In the investigation of an unknown alcohol, there was a positive Jones test and a negative Lucas test. What deductions may be
pogonyaev

Answer:

1. When observing a positive test for the jones reagent and negative for the Lucas test, it indicates that it is in the presence of a primary alcohol.

Jones reagent behaves like a strong oxidant, where it transforms the primary alcohols into carboxylic acids and the secondary alcohols into ketones. Tertiary alcohols do not react.

With the Lucas test, tertiary alcohols react immediately producing turbidity, while secondary alcohols do so in five minutes. Primary alcohols do not react significantly with Lucas reagent at room temperature.

2. No reaction (See the attached drawing)

3. (see the attached drawing)

7 0
3 years ago
A student placed a stack of rocks on a ramp. She added clumps of soil rooted with live grass. Using a garden hose, she then appl
Sliva [168]
<span>Answer D. Spray from the hose suggests water in liquid state falling into the soil. The process of elimination: A glacier can be related to water in frozen but in static state. B Fast winds has the element of movement of air, not water. C. A hail storm, movement of water in frozen state. D. Heavy rains looks to be better choice compares to the others.</span>
7 0
3 years ago
Read 2 more answers
True or False a chemical formula is a representation of the smallest unit of a compound?
trapecia [35]

Answer:

true. I think

Explanation:

A chemical formula shows the atoms a molecule is made of.

3 0
3 years ago
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