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Stels [109]
2 years ago
9

When bar-headed geese fly at very high altitudes (possibly over Mount Everest!), they breathe very thin air where the partial pr

essure of oxygen is very low compared to that at sea level. Which of the following adaptions would help the geese efficiently exchange gases when flying at high altitudes? ______
A) hemoglobin that has a high affinity for oxygen
B) hemoglobin that has a high affinity for carbon dioxide
C) hemoglobin that has a low affinity for carbon dioxide
D) hemoglobin that has a low affinity for oxygen
Chemistry
1 answer:
Reil [10]2 years ago
5 0

Answer:hemoglobin that has a high affinity for oxygen

Explanation:

Haemoglobin is the oxygen carrying pigment in blood. It performs this function because of the presence of iron at the center of the haemoglobin which coordinates reversibly with oxygen thereby aiding delivery of oxygen to cells. At high altitudes where air is thinner and the partial pressure of oxygen is lower than sea level, haemoglobin must develop a greater affinity for oxygen in order to carry the scarce oxygen to cells.

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Answer:

smoother and less jagged

Explanation:

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2 years ago
Sort the phrases based on whether they describe or give an example of diffusion, facilitated diffusion, both, or neither. note:
Bingel [31]

Question:

a. Diffusion

b. Facilitated diffusion

c. Both

d. Neither

1. movement to area of lower concentration

2. movement across a membrane

3. steroid transport into cell

4. requires energy

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Answer:

The sorting is as follows

a. (1)

b. (5 and 6)

c. (1 and 2)

d. (4)

Explanation:

Diffusion is the movement of particles across a membrane from a high concentration region to one with a lower concentration of the diffusing substance

Here we have the correct sorting as follows

a. Diffusion

3. steroid transport into cell

b. Facilitated diffusion

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c. Both

1. movement to area of lower concentration

2. movement across a membrane

d. Neither

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8 0
3 years ago
A sample of helium gas at 27.0 °C and 3.60 atm pressure is cooled in the same container to a temperature of -73.0 °C. What is th
trasher [3.6K]

Answer: The new pressure, if volume and amount of gas do not change is 2.40 atm

Explanation:

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=3.60atm\\T_1=27^0C=(27+273)K=300K\\P_2=?\\T_2=-73.0^0C=(273-73)=200K

Putting values in above equation, we get:

\frac{3.60}{300K}=\frac{P_2}{200K}\\\\P_2=2.40atm

Thus the new pressure, if volume and amount of gas do not change is  2.40 atm

5 0
3 years ago
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NemiM [27]
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