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Otrada [13]
3 years ago
15

Which graph shows a system with an infinite number of solutions?

Mathematics
1 answer:
Rom4ik [11]3 years ago
4 0
Graph b I’m pretty sure cause there parallel to each other and will keep stretching
You might be interested in
Will upvote
shepuryov [24]
\frac{a^{12}b^{8}}{a^{2}b^{4}}



remember
(ab)/(cd)=a/c times b/d

also \frac{x^{m}}{x^{n}}= x^{m-n}

split it up with like terms

\frac{a^{12}}{a^{2}} times \frac{b^{8}}{b^{4}}

do subtraction
for a's
12-2=10

b's
8-4=4

answe is a^{10}b^{4}

first one

5 0
3 years ago
Read 2 more answers
What are the chances of flipping a coin 12 times and it landing on heads 11 times?
lubasha [3.4K]
12 flips, 11 heads, 1 tails
Let's say there's a 50-50 chance of landing heads.
There are 12 flips and 12 specific outcomes.
The probability is 2^(-12) = 1/4096 = 0.0244%

If the last flip doesn't matter, then the probability would be 2^(-11) = 1/2048 = 0.0488%.

Have an awesome day! :)

From your friendly Helper-in-Training, collinjun0827
8 0
3 years ago
You make a purchase of $1,987.54 using a rewards credit card that gives you 2% cash back. If the credit card has a 17.75% APR an
AlladinOne [14]
$10.35 is the answer

7 0
4 years ago
Read 2 more answers
Anthony deposits $800 into a savings account that carns 3.5% interest annually.
Zepler [3.9K]

after 1 year he will get : 800 + 800 x 3,5% = 800 x 1,035 = $828

after 2 years he will get : 828 x 1,035 = 800 x 1,035 x 1,035 = 800 x 1,035²

so

after n years he will get : 800 x 1,035ⁿ

6 0
2 years ago
Read 2 more answers
A researcher wants to estimate the percentage of all adults that have used the Internet to seek pre-purchase information in the
lara31 [8.8K]

Answer:

The sample size is 1875.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

Sampling error of 0.03.

This means that M = 0.03

99.74% confidence level

So \alpha = 0.0026, z is the value of Z that has a pvalue of 1 - \frac{0.0026}{2} = 0.9987, so Z = 3.

25% of all adults had used the Internet for such a purpose

This means that \pi = 0.25

What is the sample size

The sample size is n. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 3\sqrt{\frac{0.25*0.75}{n}}

0.03\sqrt{n} = 3\sqrt{0.25*0.75}

Simplifying by 0.03 both sides

\sqrt{n} = 100\sqrt{0.25*0.75}

(\sqrt{n})^2 = (100\sqrt{0.25*0.75})^2

n = 1875

The sample size is 1875.

7 0
3 years ago
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