Answer:
Q = 12.38
Explanation:
The Nernst equation is given as; Ecell = E°cell - (2.303RT/nF) log Q ;where Q is the reaction quotient.
The reaction quotient, Q in a reaction, is the product of the concentrations of the products divided by the product of the concentrations of the reactants.
In an electrochemical cell, Q is the ratio of the concentration of the electrolyte at the anode to that of the electrolyte at the cathode.
Q = [anode]/[cathode]
therefore , Q = 0.052/0.0042 = 12.38
Answer:
V₂ = 6.0 mL
Explanation:
Given data:
Initial volume = 9.0 mL
Initial pressure = 500 mmHg
Final volume = ?
Final pressure = 750 mmHg
Solution:
According to Boyle's Law
P₁V₁ = P₂V₂
V₂ = P₁V₁ / P₂
V₂ = 500 mmHg × 9.0 mL / 750 mmHg
V₂ = 4500 mmHg .mL / 750 mmHg
V₂ = 6.0 mL
t1/2 = ln 2 / λ = 0.693 / λ
Where t1/2 is the half life of the element and λ is decay constant.
32 = 0.693 / λ
λ = 0.693 / 32 (1)
Nt = Nο eΛ(-λt) (2)
Where Nt is atoms at t time, λ is decay constant and t is the time taken.
t = 1.9 hours = 1.9 x 60 min
From (1) and (2),
Nt = Nο e⁻Λ(0.693/32)*1.9*60
Nt = 0.085Nο
Percentage = (Nt/Nο) x 100%
= (0.085Nο/Nο) x 100%
= 8.5%
Hence, Percentage of remaining atoms with the original sample is 8.5%
Answer:
Explanation:
Atoms are the thing that make up molecules and compounds. Molecules contain two or more atoms and are held together by covalent bonds
Boiling point is the temperature at which vapour pressure equals atmospheric pressure.
As, we move at higher altitudes, atmospheric pressure decreases. Hence, temperature to reach the boiling point will decrease.
Further, boiling point is higher for longer chain compounds. Hence,<span> octane (C8H18) and octanol (C8H17OH) will have higher boiling point as compared to hexane (C6H14). Further, intermolecular forces of interaction are more stronger in octanol, due to presence of OH group, as compared to octane.
Hence, boiling points will be in following order:
Octanol > Octane > Hexane
Thus, hexane will boil first, followed by octane and lastly octanol.</span>
