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Margaret [11]
3 years ago
10

How many atoms are in 1.15 mole Cu?

Chemistry
2 answers:
xxMikexx [17]3 years ago
4 0
6.022x10^23 is Avogadro’s number. Use this whenever you work with Stoichiometry involving Atoms, formula units, or molecules. 1 mol of anything is always Avogadro’s number.

Multiply everything on the top= 6.93 x 10^23
Divide by everything on the bottom = 6.93 x 10^23
Answer: 6.93 x 10^23 atoms Cu.

fiasKO [112]3 years ago
3 0
6.93 • 10^23 atoms Cu
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The rate constant for a first-order reaction is 0.54 s-1. What is the half-life of this reaction if the initial concentration is
Diano4ka-milaya [45]

Answer:

The half life time of first order reaction is 1.3 sec

Explanation:

Given:

First order rate constant K = 0.54 M^{-1} s^{-1}

Initial concentration = 0.54 M

From the formula of first order half life time,

  K = \frac{0.693}{t_{\frac{1}{2} } }

So half life time is given by,

{t_{\frac{1}{y2} } } = \frac{0.693}{0.54}

{t_{\frac{1}{y2} } }  = 1.3 sec

Therefore, the half life time of first order reaction is 1.3 sec.

4 0
3 years ago
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alukav5142 [94]
If one does not do so, the cut can lead to being infected with various pathogens and other Bacteria, possibly worsening the Minor injury. Thus taking additional medication and further required time to heal.
6 0
3 years ago
A compound is 75.46% Carbon, 4.43% hydrogen and 20.10% Oxygen by mass. it has a molecular weight of 318.31g/mol. what is the mol
DiKsa [7]

Answer:

No.of moles of C is , n = mass/molar mass = 75.46 g / 12 (g/mol) = 6.3 moles No.of moles of H is , n' = mass/molar mass = 4.43 g / 1.0(g/mol) = 4.43 moles No.of moles of O is , n'' = mass/molar mass = 20.10 g / 16(g/mol) =1.25 moles Ratio to the no.of moles of C,H& O is 6.3 : 4.43 : 1.25 In the simple integer ratio is ( 6.3/1.25) : ( 4.43/1.25) : (1.25/1.25) 5.04 :3.5 : 1

Explanation:

5 0
3 years ago
As with other ionic compounds, potassium bromate, KBrO3, dissociates into ions when it dissolves in water. If 13.8 g of KBrO3 is
chubhunter [2.5K]

Answer:

ΔH of dissociation is 38,0 kJ/mol

Explanation:

The dissociation reaction of KBrO₃ is:

<em>KBrO₃ → K⁺ + BrO₃⁻ </em>

This dissolution consume heat that is evidenced with the decrease in water temperature.

The heat consumed is:

q = CΔTm

Where C is specific heat of water (4,186 J/mol°C)

ΔT is the temperature changing (18,0°C - 13,0°C = 5,0°C)

And m is mass of water (150,0 mL ≈ 150,0 g)

Replacing, heat consumed is:

q = 3139,5 J ≡ 3,14 kJ

13,8 g of KBrO₃ are:

13,8 g×(1mol/167g) = 0,0826 moles

Thus, ΔH of dissociation is:

3,14kJ / 0,0826mol = <em>38,0 kJ/mol</em>

<em></em>

I hope it helps!

3 0
3 years ago
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Isn't this a math problem?
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27x10=270
270-168=102
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