
where
the Avogadro's constant that relates the number of particles to their number, in the unit moles
.
The molar mass of propanol- mass per mole propanol- can be directly deduced from its molecular formula with reference to a modern periodic table.

of propanol molecules would thus have a mass of 
Answer:
0.093 mole of C₆H₁₂.
Explanation:
We'll begin by calculating the molar mass of C₆H₁₂. This can be obtained as follow:
Molar mass of C₆H₁₂ = (12×6) + (12×1)
= 72 + 12
= 84 g/mol
Finally, we shall determine the number of mole in 7.8 g of C₆H₁₂. This can be obtained as follow:
Molar mass of C₆H₁₂ = 84 g/mol
Mass of C₆H₁₂ = 7.8 g
Mole of C₆H₁₂ =?
Mole = mass / molar mass
Mole of C₆H₁₂ = 7.8 / 84
Mole of C₆H₁₂ = 0.093 mole
Thus, 7.8 g contains 0.093 mole of C₆H₁₂.
Answer:
17 protons
19 neutrons
Explanation:
Chlorine will always have the same amount of protons, and that would be 17 protons.
The atomic mass will change according to how many neutrons are present.
Cl - 35 is comprised of 17 protons and 18 neutrons.
We want to find Cl - 36:
We simply add 1 neutron. 18 + 1 = 19 neutrons.
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