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Maru [420]
2 years ago
7

I can walk at 6km/hr and run at 15km/hr. On a journey I spend as long walking as I do running. If I had walked twice as long on

the journey it would have taken me six minutes longer find how far I ran​
Mathematics
1 answer:
const2013 [10]2 years ago
5 0

He ran for 12 km in his journey.

<h3>What is an Equation ?</h3>

An equation is formed when two algebraic expressions are equated by an equal sign.

It is given that

Speed of Walking =6km/hr  

Speed of Running = 15km/hr

Let he walks and run x hours ( as given)

he covered distance = 21 x km

The total time taken in the journey is 2x

for the same distance

It is also given that

if for the total journey

if he walks walked twice as long on the journey

He walked 6x in the journey so new distance that he walked is  12x  , then the total journey time = 6 minutes longer

Converting speed from km / hr to km/ min

1 km / hr = 60 km/ min

and forming an equation with the given data

12x * 60 /6 + 9x *60/15 = 2x * 60 + 6

120x + 36x = 120x +6

150x = 120

x = 120/150

x = 0.8 hours.

Therefore he spent 0.8 hours walking and 0.8 hours running and He ran 15 * 0.8 = 12 km

To know more about Equation

brainly.com/question/10413253

#SPJ1

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The average speed of greyhound dogs is about 18.4 meters per second. A particular greyhound breeder claims that her dogs are fas
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Answer:

The calculated value    Z = 1.183 < 1.96 at 0.05 level of significance

Null hypothesis is accepted

A particular greyhound breeder claims that her dogs are faster than the average greyhound

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given the average speed of greyhound dogs is about 18.4 meters per second.

Size of the sample 'n' = 35

mean of the sample x⁻ = 18.7

Population standard deviation = 1.5m/s

level of significance (∝)  = 0.05

<u><em>Step(ii):-</em></u>

Null hypothesis : H₀ : μ = 18.4

Alternative  hypothesis H₁ :  μ ≠ 18.4

Test statistic

              Z  = \frac{x^{-} - mean}{\frac{S.D}{\sqrt{n} } }

             Z  = \frac{18.7-18.4}{\frac{1.5}{\sqrt{35} } }

            Z = 1.183

<u><em>Conclusion:</em></u>-

The calculated value    Z = 1.183 < 1.96 at 0.05 level of significance

Null hypothesis is accepted

A particular greyhound breeder claims that her dogs are faster than the average greyhound

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Step-by-step explanation:

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7. A number of minor automobile accidents occur at various high-risk intersections in Teton County despite traffic lights. The T
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Answer:

Modification has not reduced the number of accidents.

Step-by-step explanation:

H_0: \mu\geq0\\H_a:\mu

                                 A  B  C   D   E   F  G   H

Before modification 5  7  6   4    8   9   8   10

After modification    3  7  7   0    4   6   8    2

Difference                -2 0  1   -4   -4   -3  0   -8

Mean of differences M_d = \frac{sum}{8}=\frac{2+0-1+4+4+3-0+8}{8}=2.5

Standard deviation of differences = \sqrt{\frac{\sum(x-\bar{x})^2}{n}}=2.9277

Formula of paired t test :

t=\frac{M_d}{\frac{s}{\sqrt{n}}}\\t=\frac{2.5}{\frac{2.9277}{\sqrt{8}}}\\t = 2.4152

Df = n-1 = 8-1 =7

t critical = t_{(df, \alpha)}=t_{7,0.01}=2.998

t critical> t calculated

So, We failed to reject null hypothesis

Hence modification has not reduced the number of accidents.

6 0
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