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3 years ago

Classify the special quadrilateral.

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

6 0

Answer: Rhombus

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Explanation:

The tickmarks show that all four sides are the same length. Therefore, this figure is a rhombus. It is not a square because the angle would need to be 90 degrees. We can say it is a non-square rhombus, or a rhombus that isn't a square. It is also not a rectangle either because all rectangles have each angle at 90 degrees.

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sue has 5 ropes of 5350 mm each.If she ties them together to make one long rope and each kont takes up 15 cm,how long will the r

Vsevolod [243]

Answer:

(hopefully) 2,600

Explanation:

5350 mm = 535 cm

= 535 x 5( 5 ropes) = 2675 cm

= 15 cm × 5 ( five knots for 5 ropes) = 75cm

= 2675- 75 = 2600.

hopefully im right...

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4 years ago

Read 2 more answers

The 2nd one is right just did the test

Vikki [24]

Answer:

ok lol

Step-by-step explanation:

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3 years ago

A manatee eats an average of 70 pounds of

Anton [14]

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3 years ago

A laptop producing company also produces laptop batteries, and claims that the batteries

gregori [183]

Answer:

There is enough evidence to support the claim that the batteries power the laptops for significantly less than 4 hours. (P-value = 0).

The null and alternative hypothesis are:

$H_0: \mu=4\\\\H_a:\mu< 4$

Step-by-step explanation:

The question is incomplete: To test this claim a sample or population standard deviation is needed.

We will estimate that the sample standard deviation is 2 hours, and use a t-test to test that claim.

NOTE (after solving): The difference between the sample mean and the mean of the null hypothesis is big enough to reject the null hypothesis, even when we have a sample standard deviation of 3.5 hours, which can be considered bigger than the maximum standard deviation for the sample.

This is a hypothesis test for the population mean.

The claim is that the batteries power the laptops for significantly less than 4 hours.

Then, the null and alternative hypothesis are:

$H_0: \mu=4\\\\H_a:\mu< 4$

The significance level is 0.05.

The sample has a size n=500.

The sample mean is M=3.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=2.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{2}{\sqrt{500}}=0.0894$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{3.5-4}{0.0894}=\dfrac{-0.5}{0.0894}=-5.5902$

The degrees of freedom for this sample size are:

$df=n-1=500-1=499$

This test is a left-tailed test, with 499 degrees of freedom and t=-5.5902, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t$

As the P-value (0) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the batteries power the laptops for significantly less than 4 hours.

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3 years ago

The combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 m

rewona [7]

Answer:

Approximately 50 pounds less carbon (in CO₂) will be produced by the second auto on this trip.

Step-by-step explanation:

We have been given that the combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 miles.

Let us find amount of fuel used by autos by dividing the total distance by their mileage.

$\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\frac{\text{ 20 miles}}{\text{gallon}}}$

$\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\text{ 20 miles}}\times \text{gallon}$

$\text{Fuel used by 1st auto}=30 \text{ gallons}$

$\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\frac{\text{ 30 miles}}{\text{gallon}}}$

$\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\text{ 30 miles}}\times \text{gallon}$

$\text{Fuel used by 2nd auto}=20 \text{ gallons}$

Let us find the difference of fuel used by both autos.

$\text{Number of gallons that 2nd auto used less than 1st auto}=30-20$

$\text{Number of gallons that 2nd auto used less than 1st auto}=10$

Since one gallon of automobile fuel produces about 5 pounds of carbon, so 10 gallons of fuel will produces $5\times 10=50$ pounds of carbon.

Since 2nd auto used 10 gallons less than 1st auto, therefore, 2nd auto will produce 50 pounds less carbon than 1st auto.

8 0

3 years ago