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Andru [333]
2 years ago
10

Classify the special quadrilateral.

Mathematics
1 answer:
PilotLPTM [1.2K]2 years ago
6 0

Answer: Rhombus

=====================================================

Explanation:

The tickmarks show that all four sides are the same length. Therefore, this figure is a rhombus. It is not a square because the angle would need to be 90 degrees. We can say it is a non-square rhombus, or a rhombus that isn't a square. It is also not a rectangle either because all rectangles have each angle at 90 degrees.

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The answer:

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Explanation to your question:

Since the sin of theta is 0.3, we can reasonably deduct that the opposite side to theta has a ration of 3 to 10 to that of the hypotenuse. Thus, the adjacent side to theta, using the pythagorean theorem, will be root91. Therefore, since the cosine of theta is the adjacent/hypotenuse, we get root 91/10

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In ΔEFG, the measure of ∠G=90°, EF = 95 feet, and FG = 26 feet. Find the measure of ∠F to the nearest degree.
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Answer:

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Step-by-step explanation:

Given

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As we know:

Sin(GEF)/ GF = Sin(EGF)/EF

<=> Sin(GEF) / 26 = Sin(90)/95

<=>Sin(GEF) / 26 = 1/95

<=> Sin(GEF)  = 26/95

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=> ∠F = 180° - ∠G - ∠GEF

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klasskru [66]

Answer:

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3 years ago
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