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2 years ago

PLEASE HELP (another question at the bottom)

Mathematics

2 answers:

d1i1m1o1n [39]2 years ago

8 0

Boo... boo? Boo! Tell me it’s not what I think it is xd

vfiekz [6]2 years ago

7 0

Answer:

How have u been?

Step-by-step explanation:

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170 percent converted to a fraction equals: ...?

Verdich [7]

There are several ways to do this by converting the percentage to a fraction by placing thee expression over 100100. Percentage means out of 100 and it will look like this 170/100.
Reduced the expression. 17/10
or in whole number it is 1 17/10

8 0

3 years ago

Read 2 more answers

Find the greatest common factor of 10, 30,10,30,10, comma, 30, comma and 454545.

borishaifa [10]

Answer:

GCF = 5

Step-by-step explanation:

Given:

The numbers are given as:

10, 30 and 45

A factor of a number is a number by which the given number is evenly divisible.

Example: 2 is a factor of 4 as $4\div 2 =2$ . So, 4 is evenly divisible by 2 and hence 2 is a factor of 4.

Now, factors of 10 = 1, 2, 5, 10.

Factors of 30 = 1, 2, 3, 5, 6, 10, 15, 30.

Factors of 45 = 1, 3, 5, 9, 15, 45.

So, the greatest common factor in all the three numbers is 5.

Hence, the greatest common factor of 10, 30 and 45 is 5.

5 0

3 years ago

Need help with Calculus 1 inverse trig functions

lidiya [134]

Answer:

$\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}$

Step-by-step explanation:

The Derivative of a Function

The derivative of f, also known as the instantaneous rate of change, or the slope of the tangent line to the graph of f, can be computed by the definition formula

$\displaystyle f'(x)=\lim\limits_{\Delta x \rightarrow 0}\frac{f(x+\Delta x)-f(x)}{\Delta x}$

There are tables where the derivative of all known functions are provided for an easy calculation of specific functions.

The derivative of the inverse tangent is given as

$\displaystyle (tan^{-1}u)'=\frac{u'}{1+u^2}$

Where u is a function of x as provided:

$y=3tan^{-1}(x+\sqrt{1+x^2})$

If we set

$u=(x+\sqrt{1+x^2})$

Then

$\displaystyle u'=1+\frac{2x}{2\sqrt{1+x^2}}$

$\displaystyle u'=1+\frac{x}{\sqrt{1+x^2}}$

Taking the derivative of y

$y'=3[tan^{-1}(x+\sqrt{1+x^2})]'$

Using the change of variables

$\displaystyle y'=3[tan^{-1}u]'=3\frac{u'}{1+u^2}$

$\displaystyle y'=3\frac{u'}{1+u^2}=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+(x+\sqrt{1+x^2})^2}$

Operating

$\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+x^2+2x\sqrt{1+x^2}+1+x^2}$

$\boxed{\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}}$

8 0

3 years ago

Please help me answer number 38.

julia-pushkina [17]

The request is to find the intersection of the two sets. By definition, the intersection of two sets is another set, composed by all the elements appearing in both sets.

In other words, $P\cap Q$ is the set of all elements that P and Q have in common.

P contains all the numbers from 0 to 9, V contains all the odd numbers between 1 and 19. So, their intersection will be the odd numbers between 0 and 9, i.e.

$P\cap Q=\{1, 3, 5, 7, 9\}$

5 0

3 years ago

Sophia is dilating a figure. One of her pre-image points with coordinates (-3, 5) has an image with coordinates (-9, 15). If one

Galina-37 [17]

The dilation factor Sophia is using appears to be
(image coordinate)/(original coordinate) = -9/-3 = 15/5 = 3

Then the problem tells us
(pre-image point)×3 = (3, 1)
so we conclude
(pre-image point) = (3, 1)/3 = (1, 1/3)

8 0

3 years ago

Read 2 more answers