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3 years ago

PLEASE HELP (another question at the bottom)

Mathematics

2 answers:

d1i1m1o1n [39]3 years ago

8 0

Boo... boo? Boo! Tell me it’s not what I think it is xd

vfiekz [6]3 years ago

7 0

Answer:

How have u been?

Step-by-step explanation:

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Neal decides to sell his concert tickets to a sold- out show. He paid 90$ for the pair but believes he can sell them for 150% of

Pie

Answer:

Neal thinks that he can sell the tickets for $135.

Step-by-step explanation:

Original price at which Neal bought the tickets = $90

If he expects to sell them at 150% of the original,

150% as a decimal = 150/100 = 1.5

the new resale price = 1.5* $90

= $135

Therefore, Neal thinks that he can sell the tickets for $135.

5 0

3 years ago

What is equal to the answer of 1/10=_%

Tanzania [10]

Answer:

10%

Step-by-step explanation:

1/10 = 10/100 = 10% (by definition of what percentage is)

7 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP

UNO [17]

Answer:

Step-by-step explanation:

It can be any, exept right, because the scalene, obtuse, and isosceles, they can all have an acute angle in it some where.

So, for isosceles, you have that really tiny little point. So, only the first three answers are correct. :D

4 0

3 years ago

Read 2 more answers

33. (Figure 9-2: Shrimp Market) If the government imposes a quota limiting sales of shrimp to 500

Anastasy [175]

10 I know this is going to help

5 0

2 years ago

7. By using binomial expansion show that the value of (1.01)^12 exceed the value of (1.02)^6 by 0.0007 correct to four decimal p

BlackZzzverrR [31]

Binomial expansion is used to factor expressions that can be expressed as the power of the sum of two numbers.

The proof that (1.01)^12 exceeds (1.02)^6 by 0.0007 is $\mathbf{(1.01)^{12} - (1.02)^6 \approx 0.0007 }$

The expressions are given as:

$\mathbf{(1.01)^{12}\ and\ (1.02)^6}$

A binomial expression is represented as:

$\mathbf{(a + b)^n = \sum\limits^n_{k=0}^nC_k a^{n - k}b^k}$

Express 1.01 as 1 + 0.01

So, we have:

$\mathbf{(1.01)^{12} = (1 + 0.01)^{12}}$

Apply the above formula

$\mathbf{(1.01)^{12} = ^{12}C_0 \times 1^{12 - 0} \times 0.01^0 + ......... .......... + ^{12}C_{12} \times 1^{12 - 12} \times 0.01^{12} }}$

$\mathbf{(1.01)^{12} = 1 \times 1 \times 1 + ......... .......... + 1 \times 1 \times 10^{-24} }}$

$\mathbf{(1.01)^{12} = 1 + ......... .......... + 10^{-24} }}$

This gives

$\mathbf{(1.01)^{12} = 1.1268\ (approximated)}$

Similarly,

Express 1.02 as 1 + 0.02

So, we have:

$\mathbf{(1.02)^6 = (1 + 0.02)^6}$

Apply $\mathbf{(a + b)^n = \sum\limits^n_{k=0}^nC_k a^{n - k}b^k}$

$\mathbf{(1.02)^6 = ^6C_0 \times 1^{6 - 0} \times 0.02^0 + ^6C_1 \times 1^{6 - 1} \times 0.02^1 +.............. + ^6C_6 \times 1^{6 - 6} \times 0.02^6 }$ $\mathbf{(1.02)^6 = 1 \times 1 \times 1 + 6 \times 1 \times 0.02 +.............. + 1 \times 1 \times 6.4 \times 10^{-11} }$