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OverLord2011 [107]
3 years ago
5

What is the area of a rectangle with a length of 1/2 yard and a width of 11/6

Mathematics
1 answer:
Nataly [62]3 years ago
7 0
56.................................................
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Using the 10% value to find 20% of 300
neonofarm [45]
20% * 300 = 2 * (10% * 300) = 2*30 = 60
3 0
3 years ago
Could you help me. ​
Sedbober [7]

Answer:

X-Large

Step-by-step explanation:

8 0
3 years ago
HELP HELP ME PLS I AM RUNNING OUT OF TIME!!!! HERE IS MY PROBLEM:
kramer

Answer:

Step-by-step explanation:

To write fractions with a common denominator, you will most likely need to scale some numbers up! I will explain how.

Let's try it with the fractions

2

3

and

3

12

12 is larger than 3, so we will have to multiply the 3 by some number to equal 12. (We are really finding the Least Common Multiple of the two denominators!) To do this, you have to multiply the 3 by 4, because 3x4=12. But now the numerator doesn't match the denominator. When you scale the denominator up, you have to scale the numerator up too! So the 2 must be multiplied by 4 also.

Now you have the following:

8

12

and

3

12

These fractions now have common denominators! Now they're all set for adding or subtracting fractions.

Try another:

2

6

and

3

5

: The least common multiple of 6 and 5 is 30. (the product of the denominators)

Transform each fraction by multiplying by "1":

2

6

⋅

5

5

=

10

30

and

3

5

⋅

6

6

=

18

30

One last problem:

4

9

and

7

6

What is the least common multiple of 9 and 6? Could you use 54? Absolutely, but it is not the LEAST number that you could use. How about 18? YES!

4

9

⋅

2

2

=

8

18

and

7

6

⋅

3

3

=

21

18

Ready to go...

Hope this helped!

7 0
2 years ago
If f(x)=2x-1 and g(x)=-2find [g f](x)
NeX [460]

Answer:

f(−2)=−5

g(2x−1)=−2

Step-by-step explanation:

6 0
3 years ago
4. Tres albañiles trabajaron en una construcción. Francisco trabajó el doble de horas que Eduardo y Eduardo trabajó el cuádruple
MrRa [10]

Answer:

La cantidad de horas que trabajó Hugo son 8, mientras que Eduardo trabajó 32 horas y Francisco 64 horas.

Step-by-step explanation:

En primer lugar, para determinar la ecuación que debes resolver, es conveniente establecer la variable a la que debes encontrar una solución en la ecuación. Entonces, llamas x a la cantidad de horas que trabajó Hugo.

Luego, sabes que Eduardo trabajó el cuádruple de horas de las que trabajó Hugo, esto es, cuatro veces más de las horas trabajadas por Hugo. Esto se expresa matemáticamente como 4*x.

Finalmente, Francisco trabajó el doble de horas que Eduardo, que se calcula multiplicando a las horas trabajadas por Eduardo por 2: 2*4*x= 8*x

Entre los tres hermanos trabajaron 104 horas. Esto indica que la suma de las horas trabajadas por Francisco, Eduardo y Hugo debe ser 104 horas. Esto se expresa matemáticamente como:

x + 4*x+ 8*x= 104 (Planteamiento algebraico)

Resolviendo (Procedimiento):

13*x=104

x=\frac{104}{13}

x=8

Esto significa que <u><em>la cantidad de horas que trabajó Hugo son 8</em></u>.

Eduardo trabajó 4*x, esto es 4*8, que da como resultado 32 horas. Entonces <u><em>Eduardo trabajó 32 horas.</em></u>

Por último, Francisco trabajó 8*x. Siendo x=8, entonces 8*8=64. Entonces <u><em>Francisco trabajó 64 horas.</em></u>

7 0
3 years ago
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