Answer: the reaction rate of the forward reaction increases (although it is not among the options shown).
Explanation:
1) The equation given is:
CO (g) + Cl₂ (g) ⇄ COCl₂ (g)
2) The forward reaction is:
CO (g) + Cl₂ (g) → COCl₂ (g)
3) The stoichiometry is 1 mole + 1 mole → 1 mole
4) Analysis and conclusion:
The effect of change in the conditions of an equilibrium is foreseen using Le Chatelier's principle.
Le Chatelier's principle states that a system in equilibrium will act trying to compensate the distress applied to the system.
In this case, the distress is increase in pressure.
To compensate the increase in pressure the system must act by reducing the number of moles in the system. Since the forward reaction implies the conversion of two moles of reagents into one mole of product, the more the forward reaction progress the less the number of moles will be present in the system and so the more the compensation of the increase in pressure. So the forward raction is favored by the increase in pressure.
Favoring the forwar reaction means that its rate will incrase,
Answer:the other ball hits the ground
15 seconds later
Explanation:
Answer is: CH₃-CH₂-CH₂-NH₃⁺.
Amine group (-NH₂) has neutral charge, bet when accepts one proton (H⁺) has positive charge.
Amines<span> are </span>compounds<span> that contain a </span>basic nitrogen atom<span> with a </span>lone pair of electrons<span>. Amines are </span>derivatives<span> of </span>ammonia<span>, where is one or more </span>hydrogen<span> atoms replaced by a </span>substituent<span> such as an </span>alkyl<span> or </span>aryl<span> group (in this compound propyl group).</span>
Answer: Molarity of a physiological saline solution is 0.15 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
n = moles of solute
=volume of solution in ml
Given : 0.89 g of sodium chloride in 100 ml of solution.
To calculate the moles, we use the equation:
Volume of solution = 100 ml
Molarity of physiological saline solution is 0.15 M
