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Alenkasestr [34]
4 years ago
9

which state of matter is characterized by ionized particles, no definite shape or volume, and good electrical conductivity?

Chemistry
2 answers:
guapka [62]4 years ago
8 0

Answer is: plasma.

There are five fundamental states of matter (gas, liquid, solid, plasma and Bose–Einstein condensate).  

In solid, molecules are closely packed, stiff and do not changes of shape or volume. Solid object (for example iron) does not take on the shape of its container.  

Liquids have definite volume, but no fixed shape.  

Gases (for example nitrogen and neon) not have definite volume and fixed shape, it depends on its container.  

Plasma is a an ionised gas with highly electrical conductivity.

aleksklad [387]4 years ago
4 0
Plasma is the state of matter where the substance is ionized and has no definite shape or volumen. The fact of being ionized makes the substance a good electrical conductor.
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At equilibrium, the concentrations in this system were found to be [N2]=[O2]=0.200 M and [NO]=0.600 M. N2(g)+O2(g)↽−−⇀2NO(g) If
cestrela7 [59]

Answer:

0.84M

Explanation:

Hello,

At first, the equilibrium constant should be computed because the whole situation is at the same temperature so it is suitable for the new condition, thus:

K_{eq}=\frac{[NO]^2_{eq}}{[N_2]_{eq}[O_2]_{eq}} \\K_{eq}=\frac{0.6^2}{0.2*0.2}\\ K_{eq}=9

Now, the new equilibrium condition, taking into account the change x, becomes:

9=\frac{[NO]^2_{eq}}{[N_2]_{eq}[O_2]_{eq}}\\9=\frac{[0.9+2x]^2}{[0.2-x][0.2-x]}

Nevertheless, since the addition of NO implies that the equilibrium is leftward shifted, we should change the equilibrium constant the other way around:

\frac{1}{9} =\frac{[N_2]_{eq}[O_2]_{eq}}{[NO]^2_{eq}}\\\frac{1}{9} =\frac{[0.2+x][0.2+x]}{[0.9-2x]^2}

Thus, we arrange the equation as:

\frac{1}{9} (0.9-2x)^2=(0.2+x)^2\\0.09-0.4x+4x^2=0.04+0.4x+x^2\\3x^2-0.8x+0.05=0\\x_1=0.06

Finally, the new concentration is:

[NO]_{eq}=0.9-0.06=0.84M

Best regards.

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Answer:

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Increase is the answer hopes this helps you

6 0
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Answer:

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4 0
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A mixture of carbon dioxide and hydrogen gases is maintained in a 6.68 L flask at a pressure of 2.14 atm and a temperature of 19
matrenka [14]

Answer:

The mass of hydrogen gas in the mixture: <u>w₂ = 0.433 g</u>

Explanation:

<u>According to the ideal gas equation: </u>

for an ideal gas, P.V = n_{total}.R.T

and n_{total}= n_{1}+n_{2}

Here, P: total pressure of the gases = 2.14 atm  

V: total volume of the gases = 6.68 L

T: temperature = 19 °C = 19+273.15 = 292.15K        (∵ 0°C = 273.15K)

R:  gas constant = 0.08206 L·atm·K⁻¹·mol⁻¹

n_{total}: total number of moles of gases

<u>To calculate the total number of moles of gases</u>:

n_{total} = \frac{P.V}{R.T} = \frac{2.14 atm\times 6.68 L}{0.08206 LatmK^{-}mol^{-}\times 292.15K} = <u>0.5963 moles</u>

Let, the number of moles of carbon dioxide be n₁ and number of moles of hydrogen be n₂

<u>Given:</u> mass of carbon dioxide: w₁ = 16.8 g, mass of hydrogen: w₂ = ?g

molar mass of carbon dioxide: m₁ = 44.01 g/mol, molar mass of hydrogen: m₂= 2.016 g/mol

Therefore, n_{total}= n_{1}+n_{2} =  (w₁ ÷ m₁) + (w₂ ÷ m₂)

⇒ 0.5963 mol =  (16.8 g ÷ 44.01 g/mol) + (w₂ ÷ 2.016 g/mol)

⇒ 0.5963 mol =  (0.3817mol) + (w₂ ÷ 2.016 g/mol)

⇒ 0.5963 mol - 0.3817mol = (w₂ ÷ 2.016 g/mol)

⇒ 0.2146 mol = (w₂ ÷ 2.016 g/mol)

⇒ w₂ = 0.433 g

<u>Therefore, the mass of hydrogen gas in the mixture: w₂ = 0.433 g</u>

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