Answer:
0.5667 M ≅ 0.57 M.
Explanation:
It is known that the no. of millimoles of a solution before dilution is equal to the no. of millimoles of the solution after the dilution.
It can be expressed as:
(MV) before dilution = (MV) after dilution.
M before dilution = 1.5 M, V before dilution = 340 mL.
M after dilution = ??? M, V after dilution = 340 mL + 560 mL = 900 mL.
∴ M after dilution = (MV) before dilution/(V) after dilution = (1.5 M)(340 mL)/(900 mL) = 0.5667 M ≅ 0.57 M.
Answer:
dipole-dipole
Explanation:
Intermolecular forces exists between the molecules of a substance in a particular state of matter.
The type of intermolecular forces present in a substance is determined by the electronegativity difference between the atoms that compose the substance.
There is a non zero electronegativity difference between Br and F hence the molecule is polar and the intermolecular forces between the molecules of BrF are dipole-dipole forces.
Our solar system formed about 4.5 billion years ago from a dense cloud of interstellar gas and dust. The cloud collapsed most likely due to a shockwave form a nearby exploding start called a supernova
Explanation:
The number of nitrogen atoms in one mole of nitrogen gas are <em><u>6.02214179×1023 nitrogen </u></em><em><u>atoms</u></em><em><u>.</u></em><em><u> </u></em>
<em>Hope this helps... </em>
Answer:
![\boxed{3.966 \times 10^{24}\text{ atoms of Ag}}](https://tex.z-dn.net/?f=%5Cboxed%7B3.966%20%5Ctimes%2010%5E%7B24%7D%5Ctext%7B%20atoms%20of%20Ag%7D%7D)
Explanation:
(a) Balanced equation
Cu + 2AgNO₃ ⟶ Cu(NO₃)₂+ 2Ag
(b) Calculation
You want to convert atoms of Cu to atoms of Ag.
The atomic ratio is ratio is 2 atoms Ag:1 atom Cu
![\text{Atoms of Ag} = 19.83 \times 10^{23}\text{atoms Cu} \times \dfrac{\text{2 atoms Ag}}{\text{1 atom Cu}}\\\\= 3.966 \times 10^{24}\text{ atoms of Ag}\\\\\text{The reaction will produce }\boxed{\mathbf{3.966 \times 10^{24}}\textbf{ atoms of Ag}}](https://tex.z-dn.net/?f=%5Ctext%7BAtoms%20of%20Ag%7D%20%3D%2019.83%20%5Ctimes%2010%5E%7B23%7D%5Ctext%7Batoms%20Cu%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B2%20atoms%20Ag%7D%7D%7B%5Ctext%7B1%20atom%20Cu%7D%7D%5C%5C%5C%5C%3D%203.966%20%5Ctimes%2010%5E%7B24%7D%5Ctext%7B%20atoms%20of%20Ag%7D%5C%5C%5C%5C%5Ctext%7BThe%20reaction%20will%20produce%20%7D%5Cboxed%7B%5Cmathbf%7B3.966%20%5Ctimes%2010%5E%7B24%7D%7D%5Ctextbf%7B%20atoms%20of%20Ag%7D%7D)