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Masteriza [31]
3 years ago
6

A purified protein has a molecular mass of 360 kDa when measured by size exclusion chromatography. When analyzed by gel electrop

horesis in the presence of SDS, three bands are observed, with molecular masses of 160, 140, and 60 kDa. When gel electrophoresis is carried out in the presence of SDS and dithiothreitol, three bands are once again observed, with molecular masses of 140, 80, and 60 kDa. What is the subunit composition of the protein?
Chemistry
1 answer:
Dimas [21]3 years ago
4 0

Answer:

A protein has four subunits whose molecular masses are 140, 80, and 60 kDa.

A disulfide bond links the two 80 kDa subunits (possibly identical).

Explanation:

Given that:

A protein has four subunits whose molecular masses are 140, 80, and 60 kDa.

A disulfide bond links the two 80 kDa subunits (possibly identical).

As a result of SDS and dithiothreitol analysis treatment, the molecular masses can not be 360 in total. They are 280, which implies that they are in short of 80 kDa. This means that there are possibilities that two groups with a molecular mass of 80 kDa which are joined by a disulfide bond.

The presence of SDS and dithiothreitol acts as a reducing agent, and they can break disulfide bonds whose pH is greater than 7, i.e. those in basic condition.

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Answer:

Potassium hydroxide

Explanation:

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Consider the following equilibrium: CO2(g) + C(graphite) 2CO(g); ΔH = 172.5 kJ The equilibrium constant for this reaction will
bezimeni [28]

Answer: Option (B) is the correct answer.

Explanation:

As the given reaction is as follows.

               CO_{2}(g) + C(graphite) \rightarrow 2CO(g)

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             K_{c} = \frac{[CO_{2}]}{[CO]^{2}}

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Contrast the silica content of magma in quiet and explosive eruptions
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3 years ago
A compound has a molar mass of 100 g/mol and the percent composition (by mass) of 65.45% C, 5.45% H, and 29.09% 0. Determine the
coldgirl [10]

Answer:

B) C3H3O and C6H6O2

Explanation:

Given data:

Molar mass of compound = 100 g/mol

Percentage of hydrogen = 5.45%

Percentage of carbon = 65.45%

Percentage of oxygen = 29.09%

Empirical formula = ?

Molecular formula = ?

Solution:

Number of gram atoms of H = 5.45 / 1.01 = 5.4

Number of gram atoms of O = 29.09/ 16 = 1.8

Number of gram atoms of C = 65.45 / 12 = 5.5

Atomic ratio:

            C                      :      H            :         O

           5.5/1.8              :     5.4/1.8     :        1.8/1.8

            3                      :        3          :        1

C : H : O = 3 : 3 : 1

Empirical formula is C₃H₃O.

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass = 12×3 + 1.01 ×3 + 16×1 = 55.03  

n = 100 / 5503

n = 2

Molecular formula = n (empirical formula)

Molecular formula = 2 (C₃H₃O)

Molecular formula = C₆H₆O₂

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3 years ago
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