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Masteriza [31]
3 years ago
6

A purified protein has a molecular mass of 360 kDa when measured by size exclusion chromatography. When analyzed by gel electrop

horesis in the presence of SDS, three bands are observed, with molecular masses of 160, 140, and 60 kDa. When gel electrophoresis is carried out in the presence of SDS and dithiothreitol, three bands are once again observed, with molecular masses of 140, 80, and 60 kDa. What is the subunit composition of the protein?
Chemistry
1 answer:
Dimas [21]3 years ago
4 0

Answer:

A protein has four subunits whose molecular masses are 140, 80, and 60 kDa.

A disulfide bond links the two 80 kDa subunits (possibly identical).

Explanation:

Given that:

A protein has four subunits whose molecular masses are 140, 80, and 60 kDa.

A disulfide bond links the two 80 kDa subunits (possibly identical).

As a result of SDS and dithiothreitol analysis treatment, the molecular masses can not be 360 in total. They are 280, which implies that they are in short of 80 kDa. This means that there are possibilities that two groups with a molecular mass of 80 kDa which are joined by a disulfide bond.

The presence of SDS and dithiothreitol acts as a reducing agent, and they can break disulfide bonds whose pH is greater than 7, i.e. those in basic condition.

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Read 2 more answers
There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In
adell [148]

Answer:

The net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is 523.2 kJ.

Explanation:

Step 1:

CaC_2(s) + 2H_2O(g)\rightarrow C_2H_2(g) + Ca(OH)_2(s),\Delta H_1=414.0 kJ...[1]

Step 2 :

6C_2H_2(g) + 3CO_2(g) + 4H_2O(g)\rightarrow 5CH_2CHCO_2H(g) \Delta H_2=132.0kJ..[2]

Adding 6 × [1] and [2]:

6CaC_2(s) + 12H_2O(g)\rightarrow 6C_2H_2(g) + 6Ca(OH)_2(s)

6C_2H_2(g)+3CO_2(g)+16H_2O(g)\rightarrow 5CH_2CHCO_2H(g)

we get :

6CaC_2(s) + 8H_2O(g)+3CO_2(g)\rightarrow 5CH_2CHCO_2H(g)+ 6Ca(OH)_2(s),\Delta H'=?

\Delta H'=6\times \Delta H_1+\Delta H_2

\Delta H'=6\times 414.0 kJ+132.0kJ

\Delta H'=2,626 kJ

Energy released on formation of 5 moles of acrylic acid = 2,626 kJ

Energy released on formation of 1 mole of acrylic acid:

\frac{ 2,626 kJ}{5 } = 523.2 kJ

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3 years ago
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