Acellus

Sa triangle has a base of 35cm and an area of 819 square centimeters. What is the height if the triangle?

snow_lady [41]

Height: 819/35= 23.4

5 0

3 years ago

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Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

3 years ago

What is a equivalent rational number to 1.28 repeating?

goblinko [34]

the line over the 28 means the 28 repeats forever. 1.282828.... and so on let x be the rational number 1.28... we can use this trick: 100*1.282828....= 128.282828... (the decimal 28 part repeats) 100x = 128.28... next: 100x - x = 128.282828... - 1.282828... the .282828... part will be subtracted away 99x = 127 divide both sides by 99 to get x= 127/99

3 0

3 years ago

The graph below represents the distance a pilot is from the home airport during a period of time. A graph titled Pilot's Distanc

Simora [160]

Answer:

the awswer would have to be 7

Step-by-step explanation:

4 0

3 years ago

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14. Find mMK please :)

MrRissso [65]

Answer:

Step-by-step explanation:

11) strategy: since they tell us. indirectly, that the length of JK is the same as LM then we can set those two equal, solve for X and then.. when we have X we can figure out the lenght of JK and LM and then just divide that by 2 go get PK ( :0 Player Killer ??? no , not that PK)

solve JK and LM

3x + 23 =9x-19

42 = 6x

7 = x

now that we know x = 7 plug it into either equation to come up with the length of JK or LM . I'll pick JK just b/c it was 1st

3(7) + 23 = JK

21+23 = JK

44 = JK

now take half of 1/2*JK= 22 that is PK ( are you sure that 's not player killer?)

PK = 22

12) strategy: set the two arcs BG and GC equal and solve for X, then plug x into either equation and the multiply the answer by 2 to find arc AB

9x-20 = 5x + 28

4x = 48

X = 12

9(12) -20 = BG

88 = BG

2*88 + AB

176 = AB

13) done

14) strategy: find the angle at L, and that will also be the arc of MK

copy and past the below helpful trig functions into your computer

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

copy and past the above :

use which ever trig function you want , we have all the sides of the triangle, I'll use CAH

Cos(Ф) = 9/15

Ф = arcCos(9/15)

Ф = 53.13010°

arc MK = 53.13010°

15) strategy: arc JK is just 2 times MK

2*MK = 106.26020°

arc MK = 106.26020°

16) find arc JPK strategy: JPK is just the remaining part of a full circle of 360 - MK = 253.7397°

arc JPK = 253.7397°

7 0

3 years ago